<em>Volume of blood, in (a) liters = 0.0675 liters and (b) cubic centimeters = 67.5 cm³</em>
<h3><em>Further explanation </em></h3>7 main quantities have been determined based on international standards, namely:
1. Length, meters (m)
2. Time, second (s)
3. Mass, kilograms (kg)
4. Temperature, kelvin (K)
5. Light intensity, candela (cd)
6. Electric current, ampere (A)
7. Amount of substance, mol (m)
The length of the principal is to indicate the distance between two points in a place
The symbol is usually expressed in l, length
Volume is a derivative quantity derived from the length of the principal
The unit of volume can be expressed in liters or milliliters or cubic meters
The conversion is
1 cc = 1 cm³
1 dm = 1 Liter
1 mL = 1 cm³
1 L = 1 dm³
From the question, 5 liters of blood passes through the heart in 1 minute
The heart beats 74 times/minute
So that the equation is easy as follows:
5 liters = 1 minute
74 beats = 1 minute
So that in 1 heartbeat there is as much blood volume as:
= 5 liters / 74 beats
= 0.0675 liters
When we convert to cm³ it becomes:
1 L = 1 dm³ = 10³ cm³
0.0675 liters = 0.0675.10³ cm³
= 67.5 cm³
<h3><em>Learn more </em></h3>
A city that uses ten billion BTUs of energy
what is the total mass in micrograms of cofactor
A vineyard has 145 acres of Chardonnay grapes.
Keywords: volume, liters, heart, beats, blood
Answer:4.05 s
Explanation:
Given
First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s
Both hit the ground at the same time
Let h be the height of cliff and it reaches after time t
For second stone
---2
Equating 1 &2 we get
Answer:
The other angle is 30 degrees.
Explanation:
The range of projectile is given by :
Here,
u is the speed of launch of projectile
Here,
We need to find the other launch angle when the projectile have the same range, such that,
So, the other angle is 30 degrees. Hence, this is the required solution.
Answer: 9938.8 km
Explanation:
1 pound-force = 4.48 N
30.0 pounds-force = 134.4 N
The force of gravitation between Earth and object on the surface of is given by:
Where M is the mass of the Earth, m is the mass of the object, R (6371 km) is the radius of the Earth.
At height, h above the surface of the Earth, the weight of the object:
we need to find "h"
taking the ratio of two:
Hence, Pete would weigh 30 pounds at 9938.8 km above the surface of the Earth.
Answer:
<em>a) 318.2 W/m^2</em>
<em>b) 2.5 x 10^-4 J</em>
<em>c) 1.55 x 10^-8 v/m</em>
<em></em>
Explanation:
Power of laser P = 1 mW = 1 x 10^-3 W
exposure time t = 250 ms = 250 x 10^-3 s
If beam diameter = 2 mm = 2 x 10^-3 m
then
cross-sectional area of beam A = = (3.142 x
)/4
A = 3.142 x 10^-6 m^2
a) Intensity I = P/A
where P is the power of the laser
A is the cros-sectional area of the beam
I = ( 1 x 10^-3)/(3.142 x 10^-6) = <em>318.2 W/m^2</em>
<em></em>
b) Total energy delivered E = Pt
where P is the power of the beam
t is the exposure time
E = 1 x 10^-3 x 250 x 10^-3 = <em>2.5 x 10^-4 J</em>
<em></em>
c) The peak electric field is given as
E =
where I is the intensity of the beam
E is the electric field
c is the speed of light = 3 x 10^8 m/s
= 8.85 x 10^9 m kg s^-2 A^-2
E = = <em>1.55 x 10^-8 v/m</em>