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sladkih [1.3K]
2 years ago
9

Suppose we were to attempt to use a similar machine to measure the charge-to-mass ratio of protons, instead. Suppose, for simpli

city, that we can get a "source" for a beam of protons as we do here for electrons (with a similar setup). What complications (if any) do you expect?
Physics
1 answer:
Igoryamba2 years ago
3 0

Answer:

In summary, the biggest difference in the experiment is that the proton mass is much more than the electron mass, so the voltages used are high and very dangerous.

Explanation:

The machine to measure the ratio of charge / mass of the electron, has two parts: a part where it accelerates the electrons in an electric field and a second section to charter the beam and measure its radius of curvature calculated from here the q / m ratio

In the case of having protons, the charge has the same value as that of the electrons, but with a positive charge, so the polarities of the fields should be changed.

The mass of the protons is much greater than the mass of the electrons, which introduced a significant difference in the excrement, since similar electric fields the speed of the protons is much less than the speed of the electrons, so the magnetic field through which the voters pass to have equivalent deflations in many cases this small values ​​of the magnetic field are not desirable due to the interference of the Earth's magnetic field.

Another solution could be to increase the electric field to have the protons with speeds similar to the electors, this possibility is not easy either, because the field of trunking of more than 5000 V would be needed, which are very dangerous.

In summary, the biggest difference in the experiment is that the proton mass is much more than the electron mass, so the voltages used are high and very dangerous.

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Ocean waves are observed to travel to the right along the water surface during a developing storm. A Coast Guard weather station
Nuetrik [128]

Answer:

The amplitude is  2.3 m

The Wavelength is 8.6 m

The frequency is 0.16 Hz

The time period is 6.25 sec

The equation that governs the behavior is  Y=(2.3)sin[(\frac{2\pi}{8.6} )x -(\frac{2\pi}{6.2} )t]

Explanation:

The explanation is shown on the first uploaded image

6 0
2 years ago
How much heat Q2Q2 is transferred to the skin by 25.0 gg of steam onto the skin? The heat of vaporization for steam is L=2.256×1
astraxan [27]

Answer:

56400Joules

Explanation:

The quantity of heat required is expressed as;

Q = mL

m is the mass = 25g = 0.025kg

L is the latent heat of vaporization for steam = 2.256×10^6J/kg

Substitute into the formula as shown;

Q = 0.025×2.256×10^6

Q = 56400Joules

Hence the quantity of hear required is 56400Joules

3 0
2 years ago
Alex goes cruising on his dirt bike. He rides 700m north, 300m east, 400 m north, 600m west, 1200m south, 300m east and finally
Bess [88]

Find Displacement and Distance

displacement ...

north is 700+400+100 =1200m n

south=1200m

1200-1200=0


east is 300+300=600m

west is 600m

600-600=0

back at dtart. displ zero


distance is 700+ 300m + 400 m + 600m + 1200m + 300m + 100m  = 3600m


3 0
2 years ago
You create a plot of voltage (in V) vs. time (in s) for an RC circuit as the capacitor is charging, where V=V_{0} \cdot \left(1-
creativ13 [48]

Answer:

The time constant and its uncertainty is t ± Δt = 0.526 ± 0.057 s

Explanation:

If we make a comparison we have to:

y = A*(1-e^-(C*x)) + B

If the time remains constant we have to:

t = R*C = 1/C

In this way we calculate the time constant and its uncertainty. this will be equal to:

t ± Δt = (1/1.901) ± (0.2051/1.901)*(1/1.901) = 0.526 ± 0.057 s

3 0
2 years ago
In an electricity experiment, a 1.0g plastic ball is suspended on a60-cm-long string and given an electric charge. A charged rod
alisha [4.7K]

a) Magnitude of the electric force: 3.57\cdot 10^{-3} N

b) Tension in the string: 0.010 N

Explanation:

a)

When the charged rod is brought near the ball, then the ball remains "suspended" in an inclined position. Therefore, we can analzye the forces acting in two perpendicular directions:

- Along the horizontal direction, we have the electric force F_E, pushing in one direction, and the component of the tension in the string acting in the opposite direction, T sin \theta, where T is the tension and \theta=20^{\circ} is the angle with the vertical

- Along the vertical direction, we have the weight of the ball, mg, acting downward (where m=1.0 g = 0.001 kg is the mass of the ball and g=9.8 m/s^2 is the acceleration due to gravity), and the component of the tension acting in the upward direction, T cos \theta

Therefore, since the ball is in equilibrium, we have the two equations:

T sin \theta =F_E\\Tcos \theta = mg

By dividing the two equations, we get

tan \theta=\frac{F_E}{mg}

an solving for the electric force, we find

F_E=mg tan \theta=(0.001)(9.8)tan 20^{\circ}=3.57\cdot 10^{-3} N

b)

The tension in the string can now be found by using either of the two equations above; for instance, by using the equation along the horizontal direction,

T sin \theta =F_E

Where

F_E=3.57\cdot 10^{-3} N is the electric force

\theta=20^{\circ} is the angle with the vertical

We find the tension in the string:

T=\frac{F_E}{sin \theta}=\frac{3.57\cdot 10^{-3} N}{sin 20^{\circ}}=0.010 N

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0
2 years ago
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