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son4ous [18]
1 year ago
11

Taro stated that when someone hits a golf ball with a club, the amount of energy the ball has changes, the amount of energy that

the club has changes, and the total energy of the system that includes the ball and the club increases. Which best explains Taro’s error?
Physics
2 answers:
Julli [10]1 year ago
8 0

The total energy of the system remains the same.  

Darina [25.2K]1 year ago
7 0
Taro's error is when he stated that the total energy of the ball and the club system is increasing. This is not true. The total energy of the system is not increasing. According to the first law of thermodynamics, <span>total energy of a system is always constant; energy can be transformed from one form to another however it cannot be created or destroyed. </span><span>Energy is conserved. </span>So, for this problem the total energy of the system should remain constant at all times.
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Miners find a rock that was formed from magma deep underground what type of rock could it be
andreyandreev [35.5K]
It can be an igneous rock
3 0
2 years ago
8. Rubbing a plastic bag and a balloon with a cloth gives both objects a net negative charge. The balloon's
Dafna1 [17]

Answer:

0.214 m

Explanation:

In order for the bag to levitate and not fall down, the electrostatic force between the bag and the balloon must balance the weight of the bag.

Therefore, we can write:

k\frac{q_1 q_2}{r^2}=mg

where

k is the Coulomb constant

q_1=-1\cdot 10^{-10}C is the charge on the balloon

q_2=-1\cdot 10^{-5} C is the charge on the bag

r is the separation betwen the bag and the balloon

m=0.02 g=2\cdot 10^{-5} kg is the mass of the bag

g=9.8 m/s^2 is the acceleration due to gravity

Solving for r, we find the distance at which the bag must be held:

r=\sqrt{\frac{kq_1 q_2}{mg}}=\sqrt{\frac{(9\cdot 10^9)(-1\cdot 10^{-10})(-1\cdot 10^{-5})}{(2\cdot 10^{-5})(9.8)}}=0.214 m

5 0
2 years ago
An airliner of mass 1.70×105kg1.70×105kg lands at a speed of 75.0 m/sm/s. As it travels along the runway, the combined effects o
Karo-lina-s [1.5K]

Answer:

The airliner travels 1.65 km along the runway before coming to a halt.

Explanation:

Given

Resistive forces = (2.90 × 10⁵) N = 290000 N

Mass of the airliner = (1.70 × 10⁵) kg = 170000 kg

Velocity of airliner = 75 m/s

Let the distance over moved by the airliner be equal to d

According to the work-energy theorem, the work done by the resistive forces in stopping the airliner is equal to the travelling kinetic energy of the airliner.

Work done by the resistive forces = (290000) × d = (290,000d) J

Kinetic energy of the airliner = (1/2)(170000)(75²) = 478,125,000 J

290000d = 478,125,000

d = (478,125,000/290,000)

d = 1648.7 m = 1.65 km

Hope this helps!!!

4 0
2 years ago
BRAINLIEST PLS HELP
7nadin3 [17]

Answer:

Answer:

Explanation:

It means that out of 20 students, 3 males and 1 female were digital screen addicts because they were getting dangerous amount of blue light. Thus couldn't feel calming sensation that a human feels while seeing blue light. The rest students were getting balanced blue light. So they were getting relaxed feeling while being exposed to blue light.

4 0
1 year ago
In a college homecoming competition, eighteen students lift a sports car. While holding the car off the ground, each student exe
Nata [24]

Answer:

Explanation:

Given

Each student exert a force of F=400 N

Let mass of car be m

there are 18 students who lifts the car

Total force by 18 students F=18\times 400=7200 N

therefore weight of car W=7200

mass of car m=\frac{W}{g}

m=\frac{7200}{9.8}=734.69 kg

(b)7200 N \approx 1618.624\ Pound-force

734.69 kg\approx 1619.71 Pounds                  

6 0
1 year ago
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