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son4ous [18]
2 years ago
11

Taro stated that when someone hits a golf ball with a club, the amount of energy the ball has changes, the amount of energy that

the club has changes, and the total energy of the system that includes the ball and the club increases. Which best explains Taro’s error?
Physics
2 answers:
Julli [10]2 years ago
8 0

The total energy of the system remains the same.  

Darina [25.2K]2 years ago
7 0
Taro's error is when he stated that the total energy of the ball and the club system is increasing. This is not true. The total energy of the system is not increasing. According to the first law of thermodynamics, <span>total energy of a system is always constant; energy can be transformed from one form to another however it cannot be created or destroyed. </span><span>Energy is conserved. </span>So, for this problem the total energy of the system should remain constant at all times.
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Write a hypothesis about how the height of the cylinder affects the temperature of the water. Use the "if . . . then . . . becau
IgorLugansk [536]

If the mass of the cylinder increases, the temperature of the water increases, because a greater mass means the cylinder has more potential energy that can be converted to thermal energy, increasing the temperature of the water.


4 0
2 years ago
Now suppose the initial velocity of the train is 4 m/s and the hill is 4 meters tall. If the train has a mass of 30000 kg, what
hoa [83]

Answer:

<h2>187,500N/m</h2>

Explanation:

From the question, the kinectic energy of the train will be equal to the energy stored in the spring.

Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².

Equating both we will have;

1/2 mv² = 1/2ke²

mv² = ke²

m is the mass of the train

v is the velocity of then train

k is the spring constant

e is the extension caused by the spring.

Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m

Substituting this values into the formula will give;

30000*4² =  k*1.6²

k = \frac{30,000*16}{1.6^2}\\ \\k = \frac{480,000}{2.56}\\ \\k = 187,500Nm^{-1}

The value of the spring constant is 187,500N/m

7 0
2 years ago
Neha and Suhani are playing with two identical pendulums. They leave the bob from a certain position and wait for it to return t
Anika [276]

Answer:

The correct option is C

Explanation:

The pendulum bob would return at the same time because the initial angle a pendulum bob is dropped does not affect it's period (the time it takes for the pendulum to move back and forth), however the one with a larger angle move faster but would eventually arrive at the same "starting point" due to varying displacements made.

6 0
2 years ago
Identical satellites X and Y of mass m are in circular orbits around a planet of mass M. The radius of the planet is R. Satellit
GrogVix [38]

Answer:

1) C

2) E

Explanation:

3 0
2 years ago
Nathan accelerates his skateboard uniformly along a straight path from rest to 12.5 m/s in 2.5 s.
kicyunya [14]

Answer:

<h2>a) Nathan's acceleration is 5 m/s² </h2><h2>b) Nathan's displacement during this time interval is 15.625 m</h2><h2>c) Nathan's average velocity during this time interval is 6.25 m/s</h2>

Explanation:

a) We have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = 12.5 m/s    

     Time, t = 2.5 s

     Substituting

                      v = u + at  

                      1.25 = 0 + a x 2.5

                      a = 5 m/s²

     Nathan's acceleration is 5 m/s²

b) We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = 5 m/s²  

        Time, t = 2.5 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 2.5 + 0.5 x 5 x 2.5²

                      s = 15.625 m

      Nathan's displacement during this time interval is 15.625 m

c) Displacement = 15.625 m

   Time = 2.5 s

  We have

           Displacement = Time x Average velocity

           15.625 = 2.5 x  Average velocity

           Average velocity = 6.25 m/s

     Nathan's average velocity during this time interval is 6.25 m/s

5 0
2 years ago
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