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irinina [24]
2 years ago
14

A monoatomic ideal gas undergoes an isothermal expansion at 300 K, as the volume increased from 0.010 m^3 to 0.040 m^3. The fina

l pressure is 130 kPa. What is the change in the internal (thermal) energy of the gas during this process? (R=8.31 J/mol . K) a. 0.0 kJ b. 3.6 kJ c. 7.2 kJ d.-3.6 kJ e.-7.2 kJ
Physics
1 answer:
Natali [406]2 years ago
4 0

Answer:

A) 0.0 kJ

Explanation:

Change in the internal energy of the gas is a state function

which means it will not depends on the process but it will depends on the initial and final state

Also we know that internal energy is a function of temperature only

so here the process is given as isothermal process in which temperature will remain constant always

here we know that

\Delta U = \frac{3}{2}nR\Delta T

now for isothermal process since temperature change is zero

so change in internal energy must be ZERO

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Hanging by a thread. Two metal spheres hang from nylon threads and attract each other when brought close together. (i) What can
elena-14-01-66 [18.8K]

Answer:

Explained

Explanation:

i)Two spheres hanging from nylon threads attract each other because either the two spheres are charged with opposite sign or only one of the spheres is charge so the other would be charge by induction of the charged sphere and hence attract each other.

ii)However, when they are touched the charges will be rearranged among the two sphere such that the two sphere have exact same magnitude and sign of charge and now they will repel each other or the  magnitude of charges on the two spheres become zero and they neither attract or repel each other.

5 0
2 years ago
Alex is standing still and throws a football with a speed of 10 m/s to his friend, who is also standing still. The two friends a
Phantasy [73]

The question is incomplete. It comes with a set of answer choices.


These are the answer choices:


Alex observes it as 10 m/s, and his friend observes it as less than 10 m/s.


Alex observes it as less than 10 m/s, and his friend observes it as 10 m/s.


Both Alex and his friend observe it as 10 m/s.


Both Alex and his friend observe it as less than 10 m/s.



Answer: Both Alex and his friend observe it as 10 m/s.


Justification:


1) The speed is relative to the frame of reference.


2) It is said that the both Alex and his friend are standing still.


3) Then, the speed they both see is the same, 10 m/s, respect the Earth (where they are standing still).


Of course, Alex is watching the ball moving away and his friend is seing it approaching, but it is not relevant for the question, as it deals with the speed which is only about magnitude, not direction.

7 0
2 years ago
Read 2 more answers
A metallic sphere of radius 2.0 cm is charged with +5.0-μC+5.0-μC charge, which spreads on the surface of the sphere uniformly.
sladkih [1.3K]

Answer:

Explanation:

Potential due to a charged metallic sphere having charge Q and radius r on its surface will be

v = k Q / r . On the surface and inside the metallic sphere , potential is the same . Outside the sphere , at a distance R from the centre  potential is

v = k Q / R

a ) On the surface of the shell , potential due to positive charge is

V₁ = \frac{9\times10^9\times5\times10^{-6}}{6\times10^{-2}}

On the surface of the shell , potential due to negative  charge is

V₁ = \frac{- 9\times10^9\times5\times10^{-6}}{6\times10^{-2}}

Total potential will be zero . they will cancel each other.

b ) On the surface of the sphere potential

= \frac{9\times10^9\times5\times10^{-6}}{2\times10^{-2}}

= 22.5 x 10⁵ V

On the surface of the sphere potential due to outer shell

= \frac{9\times10^9\times5\times10^{-6}}{5\times10^{-2}}

= -9 x 10⁵

Total potential

=( 22.5 - 9 ) x 10⁵

= 13.5 x 10⁵ V

c ) In the space between the two , potential will depend upon the distance of the point from the common centre .

d ) Inside the sphere , potential will be same as that on the surface that is

13.5 x 10⁵ V.

e ) Outside the shell , potential due to both positive and negative charge will cancel each other so it will be zero.

5 0
2 years ago
A stone is held at a height h above the ground. A second stone with four times the mass of the first one is held at the same hei
QveST [7]

gravitational potential energy is given by formula

U = mgh

here we need to compare the gravitational potential energy of stone 2 with respect to stone 1

so we will say

\frac{U_2}{U_1} = \frac{m_2gh}{m_1gh}

\frac{U_2}{U_1} =\frac{m_2}{m_1}

given that

m_2 = 4 m_1

now we have

\frac{U_2}{U_1} = 4

5 0
2 years ago
A certain heat engine extracts 1.30 kJ of heat from a hot temperature reservoir and discharges 0.70 kJ of heat to a cold tempera
skelet666 [1.2K]

Answer:

46%  (0.46)

Explanation:

temperature of hot reservoir (Th) = 1.3 kJ

temperature of COLD reservoir (Tc) = 0.7 kJ

Efficiency = 1 - (Tc/Th)

Efficiency = 1 - (0.7/1.3) = 0.46 = 0.46 x 100 = 46 %

7 0
2 years ago
Read 2 more answers
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