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Rudik [331]
1 year ago
15

160 students sit in an auditorium listening to a physics lecture. Because they are thinking hard, each is using 125 W of metabol

ic power, slightly more than they would use at rest. An air conditioner with a COP of 5.0 is being used to keep the room at a constant temperature.
what minimum power should be used to operate the air conditioner?
Physics
1 answer:
anastassius [24]1 year ago
8 0

Answer:

minimum power should be used to operate the air conditioner is 4000 W

Explanation:

given data

students  n = 160

power p = 125 W

COP = 5.0

to find out

what minimum power should be used

solution

we know the COP formula that is given below

COP = students × power  / minimum power

minimum power = n × p / COP

put all value

minimum power = n × p / COP

minimum power = 160 × 125 / 5

minimum power = 4000 W

minimum power should be used to operate the air conditioner is 4000 W

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Suppose the truck that’s transporting the box In Example 6.10 (p. 150) is driving at a constant speed and then brakes and slows
Scorpion4ik [409]

Answer:

Friction acts in the opposite direction to the motion of the truck and box.

Explanation:

Let's first review the problem.

A moving truck applies the brakes, and a box on it does not slip.

Now when the truck is applying brakes, only it itself is being slowed down. Since the box is slowing down with the truck, we can conclude that it is friction that slows it down.

The box in the question tries to maintains its velocity forward when the brakes are applied. We can think of this as the box exerting a positive force relative to the truck when the brakes are applied. When we imagine this, we can also figure out where the static friction will act to stop this positive force. Friction will act in the negative direction. Or in other words, friction will act in the opposite direction to the motion of the truck and box. This explains why the box slows down with the truck, as friction acts to stop its motion.

5 0
1 year ago
Which of these is the most effective way for Leanna to cool down after an intense bike ride
Sonja [21]
I am pretty sure the answer would be too stretch
6 0
2 years ago
calculate the time rate of change in air density during expiration. Assume that the lung has a total volume of 6000mL, the diame
kipiarov [429]

Answer:

The time rate of change in air density during expiration is 0.01003kg/m³-s

Explanation:

Given that,

Lung total capacity V = 6000mL = 6 × 10⁻³m³

Air density p = 1.225kg/m³

diameter of the trachea is 18mm = 0.018m

Velocity v = 20cm/s = 0.20m/s

dv /dt = -100mL/s (volume rate decrease)

= 10⁻⁴m³/s

Area for trachea =

\frac{\pi }{4} d^2\\= 0.785\times 0.018^2\\= 2.5434 \times10^-^4m^2

0 - p × Area for trachea =

\frac{d}{dt} (pv)=v\frac{ds}{dt} + p\frac{dv}{dt}

-1.225\times2.5434\times10^-^4\times0.20=6\times10^-^3\frac{ds}{dt} +1.225(-1\times10^-^4)

-1.225\times2.5434\times10^-^4\times0.20=6\times10^-^3\frac{ds}{dt} +1.225(-1\times10^-^4)

⇒-0.623133\times10^-^4+1.225\times10^-^4=6\times10^-^3\frac{ds}{dt}

           \frac{ds}{dt} = \frac{0.6018\times10^-^4}{6\times10^-^3} \\\\= 0.01003kg/m^3-s

ds/dt = 0.01003kg/m³-s

Thus, the time rate of change in air density during expiration is 0.01003kg/m³-s

3 0
2 years ago
Read 2 more answers
Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition react
kipiarov [429]

The products should she record in the last row of the table : <u>2LiCl + 3O₂</u>

<h3>Further explanation</h3>

There are several chemical reactions, namely:

  • Formation reaction
  • Decomposition reaction.
  • Replacement reaction.
  • Multiple replacement reactions
  • Neutralization reaction.
  • Combustion reaction.
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The decomposition reaction in a chemical reaction shows the decomposition reaction of a compound into its constituent elements or compounds

Rosa recorded three similar decomposition reactions

Reactions that occur :

1. 2 NaClO₃ ⇒ 2NaCl + 3O₂

2. 2KClO₃ ⇒ 2KCl + 3O₂

3. 2LiClO₃  ⇒ 2LiCl + 3O₂

There are similarities in the decomposition that forms oxygen and chloride compounds

Learn more

homogenous mixture of two or more pure substances

brainly.com/question/1832352

Keywords : products, patterns, chemical reaction, table, decomposition reactions

#LearnWithBrainly

5 0
2 years ago
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irinina [24]

Answer:

Mass of the climber = 69.38 kg

Explanation:

Change in length

        \Delta L=\frac{PL}{AE}

Load, P = m x 9.81 = 9.81m

Young's modulus, Y = 0.37 x 10¹⁰ N/m²

Area

       A=\frac{\pi (8.3\times 10^{-3})^2}{4}=5.41\times 10^{-5}m^2

Length, L = 15 m

ΔL = 5.1 cm = 0.051 m

Substituting

       0.051=\frac{9.81m\times 15}{5.41\times 10^{-5}\times 0.37\times 10^{10}}\\\\m=69.38kg  

Mass of the climber = 69.38 kg

6 0
2 years ago
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