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2 years ago

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Which of the following quantities are zero for an object traveling in a circle at a constant speed? There may be more than one c

orrect answer. Group of answer choices Velocity Acceleration Net force Radial component of velocity Tangential component of velocity Radial component of acceleration Tangential component of acceleration Radial component of net force Tangential component of net force

1 answer:

ratelena [41]2 years ago

5 0

Answer:

Zero: Tangential component of speed, Tangential component of acceleration,

Explanation:

Let's analyze uniform circular motion, using kinematics and Newton's second law , Tangency component of net force

The speed module is constant, the speed changes since its direction changes and is a vector; If there is a change in speed, there is an acceleration.

With these concepts let's analyze what quantities are zero

Quantities are:

• Acceleration. non-Zero. It is different from zero

• Net force It is different from zero

• Radial speed component. It is different from zero, change the direction

• Tangential component of speed. Zero

• radial acceleration component Non-zero

• Tangential component of acceleration. Zero

• Radial component of net force Non- Zero

• Tangency component of the net force. Zero

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A packing crate with mass 80.0 kg is at rest on a horizontal, frictionless surface. At t = 0 a net horizontal force in the +x-di

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Answer:

Final speed of the crate is 15 m/s

Explanation:

As we know that constant force F = 80 N is applied on the object for t = 12 s

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Now for next 6 s the force decreases to ZERO linearly

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now again by same equation we have

$\int F .dt = m(v_f - v_i)$

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put t = 6 s

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2 years ago

Given that an electric field of 3×106V/m3×106V/m is required to produce an electrical spark within a volume of air, estimate the

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Answer:

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Explanation:

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A turntable that is initially at rest is set in motion with a constant angular acceleration α. What is the magnitude of the angu

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Explanation:

If the turntable starts from rest and is set in motion with a constant angular acceleration α. Let $\omega$ is the angular velocity of the turntable. We know that the rate of change of angular velocity is called the angular acceleration of an object. Its formula is given by :

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$\alpha =\dfrac{\omega-0}{t}$

$\alpha =\dfrac{\omega}{t}$

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Using second equation of kinematics as :

$\theta=\omega_i t+\dfrac{1}{2}\alpha t^2$

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6 0

2 years ago

Read 2 more answers

Consider steady-state conditions for one-dimensional conduction in a plane wall having a thermal conductivity k = 50 W/m · K and

tatuchka [14]

Answer:

solution:

dT/dx =T2-T1/L

&

q_x = -k*(dT/dx)

<u>Case (1) </u>

dT/dx= (-20-50)/0.35==> -280 K/m

q_x =-50*(-280)*10^3==>14 kW

Case (2)

dT/dx= (-10+30)/0.35==> 80 K/m

q_x =-50*(80)*10^3==>-4 kW

Case (2)

dT/dx= (-10+30)/0.35==> 80 K/m

q_x =-50*(80)*10^3==>-4 kW

Case (3)

q_x =-50*(160)*10^3==>-8 kW

T2=T1+dT/dx*L=70+160*0.25==> 110° C

Case (4)

q_x =-50*(-80)*10^3==>4 kW

T1=T2-dT/dx*L=40+80*0.25==> 60° C

Case (5)

q_x =-50*(200)*10^3==>-10 kW

T1=T2-dT/dx*L=30-200*0.25==> -20° C

note:

all graph are attached

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2 years ago