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1 year ago

Pamela has three computers, all of

Physics

2 answers:

Lena [83]1 year ago

6 0

Answer:

Pamela has three computers, all of them are very old.

Explanation:

Fiesta28 [93]1 year ago

5 0

U need to write better u egg head kid or tell your mom

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Cell phone conversations are transmitted by high-frequency radio waves. Suppose the signal has wavelength 36.5 cm while travelin

tia_tia [17]

Answer:

f=8.219*10^{8}Hz

Explanation:

We are going to use the formula v=fλ

Where v= velocity of radio waves

f= frequency

λ= wavelength of wave

radio waves are electromagnetic waves and as such they have the speed of light which is 3*10^{8}m/s.

also when a wave travels from one medium to another, the wavelength changes while the frequency remains the same.

calculating for the frequency of the wave in air also gives us the frequency in the window glass.

f=\frac{v}{λ}

v=3*10^{8}m/s.

λ=36.5 cm = 36.5/100= 0.365m

f=\frac{3*10^{8}m/s.}{0.365m}

f=8.219*10^{8}Hz

7 0

2 years ago

During the 440, a runner changes his speed as he comes out of the curve onto the home stretch from 18 ft/sec to 38 ft/sec over a

Sloan [31]

Answer:

$6.67ft/s^2$

Explanation:

We are given that

Initial velocity=u=18ft/s

Final velocity,v=38ft/s

Time=t=3 s

We have to find the average acceleration over that 3 s period.

We know that

Average acceleration,a= $\frac{v-u}{t}{t}$

Using the formula

Average acceleration,a= $\frac{38-18}{3}ft/s^2$

Average acceleration,a= $\frac{20}{3}ft/s^2$

Average acceleration,a= $6.67ft/s^2$

Hence, the average acceleration= $6.67ft/s^2$

5 0

1 year ago

Consider the position vs. time graph below for a woman's movement in a hallway. What is the woman's velocity from 4 to 5 s?

Ksenya-84 [330]

Answer:

The answer is " $6\ \frac{m}{s}$ "

Explanation:

The formula for velocity:

$\to \overline{v}={\frac{\Delta x}{\Delta t}}$

$=\frac{6}{1}\\\\=6\ \frac{m}{s}$

7 0

1 year ago

1. For each of the following scenarios, describe the force providing the centripetal force for the motion: a. a car making a tur

GenaCL600 [577]

Complete Question

For each of the following scenarios, describe the force providing the centripetal force for the motion:

a. a car making a turn

b. a child swinging around a pole

c. a person sitting on a bench facing the center of a carousel

d. a rock swinging on a string

e. the Earth orbiting the Sun.

Answer:

Considering a

The force providing the centripetal force is the frictional force on the tires \

i.e $\mu mg = \frac{mv^2}{r}$

where $\mu$ is the coefficient of static friction

Considering b

The force providing the centripetal force is the force experienced by the boys hand on the pole

Considering c

The force providing the centripetal force is the normal from the bench due to the boys weight

Considering d

The force providing the centripetal force is the tension on the string

Considering e

The force providing the centripetal force is the force of gravity between the earth and the sun

Explanation:

6 0

2 years ago

A rod of mass M = 2.95 kg and length L can rotate about a hinge at its left end and is initially at rest. A putty ball of mass m

madam [21]

Answer:

Explanation:

angular momentum of the putty about the point of rotation

= mvR where m is mass , v is velocity of the putty and R is perpendicular distance between line of velocity and point of rotation .

= .045 x 4.23 x 2/3 x .95 cos46

= .0837 units

moment of inertia of rod = ml² / 3 , m is mass of rod and l is length

= 2.95 x .95² / 3

I₁ = .8874 units

moment of inertia of rod + putty

I₁ + mr²

m is mass of putty and r is distance where it sticks

I₂ = .8874 + .045 x (2 x .95 / 3)²

I₂ = .905

Applying conservation of angular momentum

angular momentum of putty = final angular momentum of rod+ putty

.0837 = .905 ω

ω is final angular velocity of rod + putty

ω = .092 rad /s .

4 0

2 years ago