If you have to apply 40n of force on a crowbar to lift a rock that weights 400n, what is the actual mechanical advantage of the
1 answer:
The mechanical advantage is defined as the ratio between the force produced by a machine and the force applied in input:
For the crowbar of the problem, the force applied in input is 40 N, while the force produced in output is equal to the weight of the rock that is lifted, so 400 N. Therefore, the mechanical advantage is
For the crowbar of the problem, the force applied in input is 40 N, while the force produced in output is equal to the weight of the rock that is lifted, so 400 N. Therefore, the mechanical advantage is
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Lets make the original number of nuclides at the start is 100.
If 7/8 of 100 is decayed, that means 87.5 decayed.
And there is 1/8 left of the number of nuclide 100. Which is 12.5
How many Half lifes passed for 100 to become 12.5 is 3 Half-Lives.
Each Half-Life is 80 seconds so there is 240 seconds
The answer is that it takes 240 seconds.
If 7/8 of 100 is decayed, that means 87.5 decayed.
And there is 1/8 left of the number of nuclide 100. Which is 12.5
How many Half lifes passed for 100 to become 12.5 is 3 Half-Lives.
Each Half-Life is 80 seconds so there is 240 seconds
Answer:
We need 4 times more force to keep the car in circular motion if the velocity gets double.
Explanation:
Lets take the mass of the car = m
The radius of the arc = r
Given that speed of the car gets double ,v' = 2 v
Then the force on the car = F'
( radius of the arc is constant)
We know that
Therefore F' = 4 F
So we can say that we need 4 times more force to keep the car in circular motion if the velocity gets double.