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Strike441 [17]
2 years ago
10

To open a door, you apply a force of 10 N on the door knob, directed normal to the plane of the door. The door knob is 0.9 meter

s from the hinge axis, and the door swings open with an angular acceleration of 5 radians per second squared. What is the moment of inertia of the door
Physics
1 answer:
Zielflug [23.3K]2 years ago
6 0

Answer:

The moment of inertia is I  = 1.8 \ kg m^2

Explanation:

From the question we are told that

   The force applied is  F  =  10 \ N

    The distance of the knob to the hinge is  d =  0.9 \ m

     The angular acceleration is  a =  5 \ rad/s

The moment is mathematically represented as

        I   =  \frac{d Fsin(\theta)}{a}

Here \theta = 90^o This is because the force direction is perpendicular to the plane of the door

substituting values

          I  =  \frac{0.9 * 10 * sin (90)}{5}

          I  = 1.8 \ kg m^2

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Answer: Thermal comductivity (K) is 3.964x 10 ^-3 W/m.k

Explanation:

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L= Distance between two isothermal planes = 0.740mm

A= Area of the surface in square metres = 2m^2

∆T= Temperature change = (37-30) °C.

Solving this : K =( 75 x 0.740 x 10^-3)/ 2 x (37-30)

K = 3.964x 10 ^-3 W/m.k

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Susie walks 3 blocks north to the local CVS store, then 4 blocks east to her grandmother’s house. She then walks 2 blocks west a
Slav-nsk [51]

Answer:

Suzie is 3 blocks north of where she started

Explanation:

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Here, Suzie first walks 3 blocks north. From there she walks 4 blocks east. Then 2 blocks to the east then 2 blocks north and then 2 blocks east. She covered 4 blocks east toward west. This is the same distance she covered traveling east. But she is 2 blocks north. From there she traveled a block south to the pizzeria and another block to her friends house. She covered the two block she had traveled north.

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2 years ago
You are boiling pasta and absentmindedly grab a copper stirring spoon rather than your wooden spoon. The copper spoon has a 20 m
11111nata11111 [884]

The spoon to transfer 40 J of energy to your hand is descibed as follows

<u>Explanation:</u>

Given  area of cross section of copper spoon is A = 20mm into 1.5 mm

temperature difference is DT = (100 minus 35) = 65 0C

length of the spoon is l = 18 cm,

amount of heat should be transfer Q = 40 J

coefficient of thermal conductivity of copper k = 400 W by mk

we know that the thermal conductivity is Q by t = k into A into DT by l

t = Q into l by k into A into DT

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2 years ago
A child's toy consists of a m = 36 g monkey suspended from a spring of negligible mass and spring constant k. When the toy monke
kolezko [41]

Answer:

Part A - 3N/m

Part B - see attachment

Part C - 4.9 × 10-³J

Part D - E = 1/2kd² + 1/2mv² + mgh

Explanation:

This problem requires the knowledge of simple harmonic motion for cimplete solution. To find the spring constant in part A the expression relating the force applied to a spring and the resulting stretching of the spring (hooke's law) is required which is F = kx.

The free body diagram can be found in the attachment. Fp(force of pull), Ft(Force of tension) and W(weight).

The energy stored in the pring as a result of the stretching of d = 5.7cm is 1/2kd².

Part D

Three forces act on the spring-monkey system and they do work in different forms: kinetic energy 1/2mv² , elastic potential

energy due to the restoring force in the spring or the tension force 1/2kd², and the gravitational potential energy mgh of the position of the system. So the total energy of the system E = 1/2kd² + 1/2mv² + mgh.

8 0
2 years ago
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