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Anon25 [30]
2 years ago
14

In the context of energy transfers with hot and cold reservoirs, the sign convention is that _______________.

Physics
1 answer:
Likurg_2 [28]2 years ago
8 0

Answer:

B. QC > 0; QH < 0

Explanation:

Given that there are two reservoir of energy.

Sign convention for heat and work :

1.If the heat is adding to the system then it is taken as positive and if heat is going out from the system then it is taken as negative.

2. If the work is done on the system then it is taken as negative and if the work is done by the system then it is taken as positive.

From hot reservoir heat is going out that is why it is taken as negative

Q_H

From cold reservoir heat is coming inside the reservoir that is why it is taken as positive

Q_C>0

That is why the answer will be

Q_H ,Q_C>0

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Two balls with charges +Q and +4Q are separated by 3R. Where should you place another charged ball Q0 on the line between the tw
azamat

Answer:

yes independent of the sign or valve of Q

Explanation:

7 0
2 years ago
A variable-length air column is placed just below a vibrating wire that is fixed at both ends. The length of the air column, ope
pogonyaev

Answer:

The speed of transverse waves in the wire is 234.26 m/s.

Explanation:

Given that,

Length of wire = 129 cm

Speed of sound in air = 340 m/s

First position of resonance = 31.2 cm

We need to calculate the wavelength

For pipe open at one end and closed at other, there is node at closed end and an anti node at open end for 1st resonance.

At 1st resonance,

L=\dfrac{\lambda}{4}

\lambda=4\times L

Put the value into the formula

\lambda=4\times31.2\times10^{-2}

\lambda=1.248\ m

We need to calculate the frequency of sound in pipe

Using formula of frequency

f=\dfrac{v}{\lambda}

Put the value into the formula

f=\dfrac{340}{1.248}

f=272.4\ Hz

We need to calculate the node distance

For the wire, there are 3 segments, so 4 nodes

Node-node distance ,

L=\dfrac{l}{3}

L = \dfrac{129}{3}

L=43\ cm

We need to calculate the wavelength of the wire

Using formula of length

L=\dfrac{\lambda}{2}

\lambda=L\times 2

Put the value into the formula

\lambda=43\times2

\lambda=86\ cm

We need to calculate the speed of the wave

Using formula of frequency

f=\dfrac{v}{\lambda}

v=f\times\lambda

Put the value into the formula

v=272.4\times86\times10^{-2}

v=234.26\ m/s

Hence, The speed of transverse waves in the wire is 234.26 m/s.

4 0
2 years ago
You place a 500 g block of an unknown substance in an insulated container filled 2 kg of water. The block has an initial tempera
Nina [5.8K]

Answer:

3349J/kgC

Explanation:

Questions like these are properly handled having this fact in mind;

  • Heat loss = Heat gained

Quantity of heat = mcΔ∅

m = mass of subatance

c = specific heat capacity

Δ∅ = change in temperature

m₁c₁(∅₂-∅₁) = m₂c₂(∅₁-∅₃)

m₁ = mass of block = 500g = 0.5kg

c₁  = specific heat capacity of unknown substance

∅₂ = block initial temperature = 50oC

∅₁ = equilibrium temperature of block and water after mix= 25oC

m₂= mass of water = 2kg

c₂ = specific heat capacity of water = 4186J/kg C

∅₃ = intial temperature of water = 20oC

0.5c₁(50-25) = 2 x 4186(25-20)

And we can find c₁ which is the unknown specific heat capacity

c₁ = \frac{2*4186*5}{0.5*25}= 3348.8J/kg C≅ 3349J/kg C

4 0
1 year ago
The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of
Harrizon [31]

Answer: T = 692.82 and 346.4 N

Explanation:

Given that;

w = 600 N

∅ = 30°

ΣFy = ma

a = 0 m/s²

ΣF = T(cos30°) - W = 0

T(cos30°) = W

we Divide both sides by cos30°

T = W / cos30o

T= 600N / cos30°

T = 692.82

and ∑fx

F = T sin∅

F = 692.82 × (sin30°)

F = 346.4 N

4 0
2 years ago
The muzzle velocity of a gun is the velocity of the bullet when it leaves the barrel. The muzzle velocity of one rifle with a sh
Anvisha [2.4K]

Answer:small barrel gun

Explanation:

Given

Muzzle velocity of bullet is greater in short barrel gun as compared to larger barrel gun

acceleration is given by change in velocity with respect to time

a=\dfrac{\Delta v}{\Delta t}

In case of short barrel bullet time taken by bullet to reach its muzzle velocity is less therefore acceleration of small barrel bullet is more compared to long barrel bullet.

7 0
1 year ago
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