A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of
1 answer:
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The intensity is defined as the ratio between the power emitted by the source and the area through which the power is calculated:
(1)
where
P is the power
A is the area
In our problem, the intensity is
. At a distance of r=6.0 m from the source, the area intercepted by the radiation (which propagates in all directions) is equal to the area of a sphere of radius r, so:
And so if we re-arrange (1) we find the power emitted by the source:
where
P is the power
A is the area
In our problem, the intensity is
And so if we re-arrange (1) we find the power emitted by the source:
Answer:
to the right.
to in the upwards direction.
Explanation:
In order to solve this problem, we must first start by drawing a diagram of the situation. (See attached diagram).
So, remember that a force is determined by multiplying the mass of the parcticle by its acceleration:
F=ma
so in order to find the components of the force, we need to start by finding its acceleration.
Acceleration is found by using the following formula:
so we can subtract the two vectors, like this:
which yields:
or:
so now I can find the components of the force:
which yields:
F=(2.31i+2.1j)N
so the components of the force are:
to the right.
to in the upwards direction.
