To solve this problem it is necessary to use the given proportions of power and energy, as well as the energy conversion factor in Jules to Calories.
The power is defined as the amount of energy lost per second and whose unit is Watt. Therefore the energy loss rate given in seconds was
The rate of energy loss per day would then be,
That is to say that Energy in Jules per lost day is 5356800J
By definition we know that 
In this way the energy in Cal is,
The number of kilocalories (food calories) must be 1279.694 KCal
Answer:
Expression of work done is
Work done to move the sled is given as 1.94 J
Explanation:
As we know that the formula of work done is given as
here we know that
F = 6 N
d = 0.4 m
so we will have
The molar latent enthalpy of boiling of iron at 3330 K is ΔH = 342 
10^3 J.
<u>Explanation:</u>
Molar enthalpy of fusion is the amount of energy needed to change one mole of a substance from the solid phase to the liquid phase at constant temperature and pressure.
d ln p = (ΔH / RT^2) dt
(1/p) dp = (ΔH / RT^2) dt
dp / dt = p (ΔH / RT^2) = 3.72 10^-3
(p) (ΔH) / (8.31) (3330)^2 = 3.72 10^-3
ΔH = 342 10^3 J.
Answer:
Explanation:
The standard form of the 2nd order differential equation governing the motion of mass-spring system is given by
Where m is the mass, ζ is the damping constant, and k is the spring constant.
The spring constant k can be found by
The damping constant can be found by
Finally, the mass m can be found by
Where g is approximately 32 ft/s²
Therefore, the required differential equation is
The initial position is
The initial velocity is
Answer:
Bounce 1 , pass 3, emb2
Explanation:
(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle. So it is Bounce1, pass3, emb2.
