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2 years ago

four children pull on the same stuffed toy at the same time , yet there is no net force on the toy.how is this possible?

2 answers:

7 0

If you and I were playing " tug-a-war " and we both pull on opposite sides with the same amount of force no one would move, the rope would be still, because the same force is on both sides of it.

Kay [80]2 years ago

3 0

There was no net force on the stuffed toy, because the kids might have the same strength, The same force is on both sides of it. T<span>hey cancel each other out. They exert a force on the stuffed toy equal in strength but opposite in direction. The forces are balanced and the stuffed toy does not move. </span>Its like a game of tug-o-war, but you and I have the same strength. the rope would be still and not moving.

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An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th

stepan [7]

Answer:

Number of photons travel through pin hole= $6.4*10^{17}$

Explanation:

First we will calculate the energy of single photon using below formula:

$E=\frac{h*c}{λ}$

Where :

h is plank's constant with value $6.626*10^{-34} J.s$

c is the speed of light whch is $3*10^{8}$

λ is the wave length = 532nm

$E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}$

E= $3.73*10^{-19}$ J

Number of photons emitted per second:

$\frac{5J/s}{1 photon/3.73*10^{-19} }$

Number of photons emitted per second= $1.34*10^{19} photons/s$

$\frac{A-hole}{A-beam}$ = $\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }$

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

$\frac{A-hole}{A-beam}$ = $\frac{d-hole^2}{d-beam^2}$

$\frac{Ahole}{A-beam}$ = $\frac{1.22^2}{5.5^2}$

$\frac{A-hole}{A-beam}$ = $\frac{144}{3025}$

Number of photons travel through pin hole= $1.34*10^{19} *\frac{144}{3025}$

Number of photons travel through pin hole= $6.4*10^{17}$

7 0

2 years ago

Which of the following relationships must be true according to the laws of series and parallel connections? (Select only relatio

tester [92]

Answer:

Explanation:

a False

b True

c True

d False

e False

f False

g True

h False

i False

4 0

2 years ago

A gas laser has a cavity length of 1/3 m and a single oscillation frequency of 9.0 x 1014 Hz. What is the cavity mode number?

Eddi Din [679]

Answer:

2 × 10⁶

Explanation:

Data provided in the question:

Cavity length, L = $\frac{1}{3}m$

Oscillation frequency, $f_m$ = 9.0 × 10¹⁴ Hz

Now,

we know,

$f_m=\frac{c}{\lambda_m}$

here,

c is the speed of light = 3 × 10⁸ m/s

$\lambda_m$ = Wavelength of mode m inside the laser cavity

m is the cavity mode number

Thus,

$9.0\times10^{14}=\frac{3\times10^8}{\lambda_m}$

$\lambda_m$ = $\frac{1}{3}$ × 10⁻⁶

Also,

$m\lambda_m = 2L$

Therefore,

m × $\frac{1}{3}$ × 10⁻⁶ = 2 × $\frac{1}{3}$

m = 2 × 10⁶

5 0

2 years ago

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this

svlad2 [7]

Answer: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation: On Edgenuity!!

7 0

2 years ago

Find the object's speeds v1, v2, and v3 at times t1=2.0s, t2=4.0s, and t3=13s.

Burka [1]

Since this is a distance/time graph, the speed at any time is the slope
of the part of the graph that's directly over that time on the x-axis.

At time t1 = 2.0 s
That's in the middle of the first segment of the graph,
that extends from zero to 3 seconds.
Its slope is 7/3 . v1 = 7/3 m/s .

At time t2 = 4.0 s
That's in the middle of the horizontal part of the graph
that runs from 3 to 6 seconds.
Its slope is zero.
v2 = zero .

At time t3 = 13 s.
That's in the middle of the part of the graph that's sloping down,
between 11 and 16 seconds.
Its slope is -3/5 . v3 = -0.6 m/s .

7 0

2 years ago

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