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ss7ja [257]
2 years ago
6

In this problem you are to consider an adiabaticexpansion of an ideal diatomic gas, which means that the gas expands with no add

ition or subtraction of heat.
Assume that the gas is initially at pressure p0, volume V0, and temperature T0. In addition, assume that the temperature of the gas is such that you can neglect vibrational degrees of freedom. Thus, the ratio of heat capacities is γ=Cp/CV=7/5.

Note that, unless explicitly stated, the variable γ should not appear in your answers--if needed use the fact that γ=7/5 for an ideal diatomic gas.

Part A

Find an analytic expression for p(V), the pressure as a function of volume, during the adiabatic expansion.

Express the pressure in terms of V and any or all of the given initial values p0, T0, and V0.

Correct

p(V) =
p0(V0V)75

Part B

At the end of the adiabatic expansion, the gas fills a new volume V1, where V1>V0. Find W, the work done by the gas on the container during the expansion.

Express the work in terms of p0, V0, and V1. Your answer should not depend on temperature.

Part C

Find ΔU, the change of internal energy of the gas during the adiabatic expansion from volume V0 to volume V1.

Express the change of internal energy in terms of p0, V0, and/or V1.

Need Part B and C

Physics
1 answer:
LenKa [72]2 years ago
6 0

Answer:

a)

The analytic expression for p(V) is P(V) = P_{0}(\frac{V_{0}}{V})^{7/5}

b)

The expression of the work in terms of p0 ,V0,V1 is

          W= \frac{5}{2} P_{0}[V_{0}-V_{0}^{7/5}V_{1}^{-2/5}]

c)

The change in internal energy of the gas

     \delta U = \frac{5}{2}P_{0}[V_{0}^{7/5}V_{1}^{-2/5}-V_{0}]

Explanation:

The explanation is shown on the first, second and third

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<h3><u>Answer;</u></h3>

= 1.256 m

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