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aniked [119]
1 year ago
9

Kai takes a hamburger off of the grill and puts a piece of cheese on it. Explain how and why the cheese melts when Kai puts it o

n the hamburger.
Physics
2 answers:
egoroff_w [7]1 year ago
5 0

Sample Response: The piece of cheese melts when it’s placed on the hamburger because conduction occurs. The hamburger is warmer than the cheese, so thermal energy is transferred from the hamburger to the cheese, causing it to melt.

Correct one for e2020

Svetllana [295]1 year ago
4 0
If Kai takes the burger off of the grill and puts cheese on it, it melts because the burger still is hot from being on the grill. The heat in and on the burger doesn’t go away immediately, so that is how and why the cheese melts.
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Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m
Alja [10]

Answer : Zamir's displacement and Talia's displacement is equal.

Explanation :

Displacement is explained to be the changing position of an object.

Zamir covers total distance 27 m and Talia covers total distance 19 m but  Zamir's initial and final position and Talia's initial and final position is same.

So, we can say that Zamir's displacement and Talia's displacement is equal.

6 0
1 year ago
Read 2 more answers
Rank the following situations according to the magnitude of the impulse of the net force, from largest value to smallest value.
wolverine [178]

Answer:

V

I and II

III and IV

Explanation:

The impulse is equal to the change in momentum of the object involved, so we can calculate the change in momentum in each situation and compare them all.

Taking always east as positive direction, and labelling

u the initial velocity

v the final velocity

m = 1000 kg the mass (which is always equal)

We find:

(i)

u = 25 m/s

v = 0

|I|=m(v-u)=(1000)(0-25)=25,000 Ns

(II)

u = 25 m/s

v = 0

|I|=m(v-u)=(1000)(0-25)=25,000 Ns

(III)

In this case,

F = 2000 N is the force

\Delta t = 10 s is the time

So the magnitude of the impulse is

|I| =F\Delta t = (2000N)(10)=20,000 Ns

(IV)

F = 2000 N is the force

\Delta t = 10 s is the time

So the magnitude of the impulse is

|I| =F\Delta t = (2000N)(10)=20,000 Ns

(V)

u = 25 m/s

v = -25 m/s

|I|=m(v-u)=(1000)(-25-25)=50,000 Ns

So the ranking from largest to smallest is:

V

I and II

III and IV

5 0
2 years ago
Calculate the volume of a liquid with a density of 5.45 g/ml and a mass of 65g
katrin [286]
Density=mass/volume
5.45g/ml=65g/V
V=65g/5.42g/ml
V=11.92ml
5 0
2 years ago
When a car drives along a "washboard" road, the regular bumps cause the wheels to oscillate on the springs. (What actually oscil
marishachu [46]

Answer:

a) 40,000 N/m

b) f = 6.37 Hz

c) v = 4,8 m/s

Explanation:

part a)

First in order to estimate the spring constant k, we need to know the expression or formula to use in this case:

k = ΔF / Δx

Where:

ΔF: force that the men puts in the car, in this case, the weight.

Δx: the sinking of the car, which is 2 cm or 0.02 m.

With this data, and knowing that there are four mens, replace the data in the above formula:

W = 80 * 10 = 800 N

This is the weight for 1 man, so the 4 men together would be:

W = 800 * 4 = 3200 N

So, replacing this data in the formula:

k = 3200 / 0.02 = 160,000 N/m

This means that one spring will be:

k' = 160,000 / 4 = 40,000 N/m

b) An axle and two wheels has a mass of 50 kg, so we can assume they have a parallel connection to the car. If this is true, then:

k^n = 2k

To get the frequency, we need to know the angular speed of the car with the following expression:

wo = √k^n / M

M: mass of the wheel and axle, which is 50 kg

k = 40,000 N/m

Replacing the data:

wo = √2 * 40,000 / 50 = 40 rad/s

And the frequency:

f = wo/2π

f = 40 / 2π = 6.37 Hz

c) finally for the speed, we have the time and the distance, so:

V = x * t

The only way to hit bumps at this frequency, is covering the gaps of bumping, about 6 times per second so:

x: distance of 80 cm or 0.8 m

V = 0.8 * 6 =

V = 4.8 m/s

5 0
2 years ago
Three magnets are placed on a plastic stick as shown in the image. Explain how the magnets need to be rearranged so that they st
dimaraw [331]

Answer:

The magnets need to be placed with red closest to blue.

Opposite poles attract.

The magnets will be attracted to each other with enough force to stick together.

Explanation:

6 0
2 years ago
Read 2 more answers
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