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aniked [119]
2 years ago
9

Kai takes a hamburger off of the grill and puts a piece of cheese on it. Explain how and why the cheese melts when Kai puts it o

n the hamburger.
Physics
2 answers:
egoroff_w [7]2 years ago
5 0

Sample Response: The piece of cheese melts when it’s placed on the hamburger because conduction occurs. The hamburger is warmer than the cheese, so thermal energy is transferred from the hamburger to the cheese, causing it to melt.

Correct one for e2020

Svetllana [295]2 years ago
4 0
If Kai takes the burger off of the grill and puts cheese on it, it melts because the burger still is hot from being on the grill. The heat in and on the burger doesn’t go away immediately, so that is how and why the cheese melts.
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Two runners ran side by side each holding one end of a horizontal pole. What would most likely happen if one of the runners bega
Anettt [7]

Answer:

See explanation.

Explanation:

If each runner was holding the pole, the runner in the water side of the pole would probably be behind the other runner. Since running in knee deep is hard and makes you slower, the pole would be slanted.

5 0
2 years ago
This is a physical property of all visible light determined by the light's frequency and visible to the human eye.
motikmotik
Color <span>is a physical property of all visible light determined by the light's frequency and visible to the human eye.</span>
6 0
2 years ago
A shuttle on Earth has a mass of 4.5 E 5 kg. Compare its weight on Earth to its weight while in orbit at a height of 6.3 E 5 met
faltersainse [42]

Answer:

83%

Explanation:

On the surface, the weight is:

W = GMm / R²

where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.

In orbit, the weight is:

w = GMm / (R+h)²

where h is the height of the shuttle above the surface of the Earth.

The ratio is:

w/W = R² / (R+h)²

w/W = (R / (R+h))²

Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:

w/W = (6.4×10⁶ / 7.03×10⁶)²

w/W = 0.83

The shuttle in orbit retains 83% of its weight on Earth.

4 0
2 years ago
A straight wire carries a current of 3 A which is in the plane of this page, pointed toward the top of the page. A particle of c
Ilia_Sergeevich [38]

Answer:

The magnitude of the magnetic force exerted on the moving charge by the current in the wire is 2.18 x 10^{-8} N

The direction of the magnetic force exerted on the moving charge by the current in the wire is radially inward

Explanation:

given information:

current, I = 3 A

q_{0} = +6.5 x 10^{-6} C

r = 0.05 m

v = 280 m/s

and direction of the magnetic force exerted on the moving charge by the current in the wire, we can use the following formula:

F = qvB sin θ

where

F = magnetic force (N)

q = electric charge (C)

v = velocity (m/s)

θ = the angle between the velocity and magnetic field

to find B we use

B = μ_{0}I/2πr

μ_{0} = 4π x 10^{-7} or 1.26 x 10^{-6} N/A^{2} , thus

B = 4π x 10^{-7} x 3 / 2π(0.05)

  = 1.2  x  10^{-5} T

Now, we can calculate the magnitude force

F = qvB sin θ

θ = 90°, because the speed and magnetic are perpendicular

F = 6.5 x 10^{-6} x 280  x 1.2 x  10^{-5} sin 90°

  = 2.18 x 10^{-8} N

Using the hand law, the magnetic direction is radially inward

8 0
2 years ago
A single crystal of aluminum is oriented for a tensile test such that its slip plane normal makes angle of 28.1 with the tensil
NISA [10]

Answer:

we have to find out the critical resolved shear stress. As it it given in the question

Ф = 28.1°and the possible values for λ are 62.4°, 72.0° and 81.1°.

a) Slip will occur in the direction where cosФ cosλ are maximum. Cosine for all possible λ values are given as follows.

cos(62.4°) = 0.46

cos(72.0°) = 0.31

cos(81.1°) = 0.15

Thus, the slip direction is at the angle of 62.4° along the tensile axis.

b) now the critical resolved shear stress can be find out by the following equation.

τ_{crss} = σ_{Y} ( cosФ cosλ)_{max}

now by putting values,

     = (1.95MPa)[ cos(28.1) cos(62.4)] = 0.80 MPa (114 Psi) 7.23

3 0
2 years ago
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