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NARA [144]
2 years ago
8

When a driver presses the brake pedal, his car stops with an acceleration of -2.1 m/s2. How far will the car travel while coming

to a complete stop if its initial speed was 13 m/s?
Physics
1 answer:
Burka [1]2 years ago
8 0
The kinematic equation that will be used for this problem is:
Vf^2 = V1^2 + 2 * a * d, where, 
Vf = final velocity = 0 m/s
V1 = initial velocity = 13 m/s
a = acceleration = -2.1m/s^2
d = distance traveled = ?
Inserting the given values, the equation becomes
0^2 = 13^2 + 2 * -2.1 * d
0 = 169 + - 4.2*d
169 = 4.2 * d
169/4.2 = d = 40.24
Therefore, d = 40.24 M.
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2 years ago
Consider a very small hole in the bottom of a tank 17.0 cm in diameter filled with water to a heightof 90.0 cm. Find the speed a
umka21 [38]

Answer:

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Explanation:

Given that,

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2 years ago
Astronomers have discovered a new planet called "Xandar" beyond the orbit of Pluto (No, not really but I need a fake planet for
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Answer:

m = 1.82E+23 kg

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r = radius of orbit = 72,600 km = 7.26E+07 m

C = circumference of orbit = 2πr = 4.56E+08 m

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v = orbital velocity of satellite Jim = C/P = 409 m/s

m = mass of Xandar = to be determined

v = √(Gm/r)

v² = [√(Gm/r)]²

v² = Gm/r

rv² = Gm

rv²/G = m

m = rv²/G

mG = universal gravitational constant = 6.67E-11 N·m²/kg²

r = radius of orbit = 72,600 km = 7.26E+07 m

C = circumference of orbit = 2πr = 4.56E+08 m

P = period of orbit = 12.9 d = 1,114,560 s

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v = √(Gm/r)

v² = [√(Gm/r)]²

v² = Gm/r

rv² = Gm

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m = rv²/G

m = 1.82E+23 kg

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