Answer:
9.98 m/s
Explanation:
The force acting on the particle is defined by the equation:
[N]
where x is the position in metres.
The acceleration can be found by using Newton's second law:
where
m = 150 g = 0.150 kg is the mass of the particle. Substituting into the equation,
[m/s^2]
When x = 3.14 m, the acceleration is:
Now we can find the final speed of the particle by using the suvat equation:
where
u = 8.00 m/s is the initial velocity
v is the final velocity
x = 3.14 m is the displacement
Solving for v,
And the speed is just the magnitude of the velocity, so 9.98 m/s.
You first us 1/2(mv^2) to solve for the potential energy and then put that in to PE=m*g*h and solve for hight
Answer:
83%
Explanation:
On the surface, the weight is:
W = GMm / R²
where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.
In orbit, the weight is:
w = GMm / (R+h)²
where h is the height of the shuttle above the surface of the Earth.
The ratio is:
w/W = R² / (R+h)²
w/W = (R / (R+h))²
Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:
w/W = (6.4×10⁶ / 7.03×10⁶)²
w/W = 0.83
The shuttle in orbit retains 83% of its weight on Earth.
Answer:
26.67 m/s
Explanation:
From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.
p=mv where p is momentum, m is the mass of object and v is the speed of the object
Initial momentum
The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero
Final momentum
F=ma
For the first (10kg) cart,
12=10a
a=6/5 m/s^2 to the left
For the second (5kg) cart,
8=5a
a=8/5 m/s^2 to the left
Therefore, the lighter (5kg) cart experiences a greater acceleration.
