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zysi [14]
2 years ago
8

A 60.0 kg object is moving east at 8.00 m/s, and then slows down to 4.00 m/s. How much work was done?

Physics
2 answers:
Artist 52 [7]2 years ago
8 0
The answer is  -1440. That is letter A.
almond37 [142]2 years ago
3 0

Answer:

Work done, W = -1440 J

Explanation:

It is given that,

Mas of an object, m = 60 kg

Initial velocity of the object, u = 8 m/s

Final velocity of an object, v = 4 m/s

We know that work done is equal to change in kinetic energy of an object as per work energy theorem.

W=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

W=\dfrac{1}{2}m(v^2-u^2)

Putting all the values in above equation we get :

W=\dfrac{1}{2}\times 60\ kg((4\ m/s)^2-(8\ m/s)^2)

W = -1440 J

So, the work done by the object is -1440 Joules. Hence, the correct option is (A) " -1440 J ".

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Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current densityJ=2.8\times10^{7}\ A/m^2

We need to calculate the current

Using formula of current density

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Put the value into the formula

I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2

I=1.97=2.0\ A

Hence, The current is 2.0 A.

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2 years ago
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Given that,

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since,

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8 0
2 years ago
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