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xxMikexx [17]
2 years ago
12

Imagine you derive the following expression by analyzing the physics of a particular system: M= (mv2r)(mGr2). Simplify the expre

ssion for M using the techniques mentioned above.
Physics
1 answer:
alex41 [277]2 years ago
3 0

Answer:

The simplified expression is M  =  \frac{v^2 r}{G}

Explanation:

From the question we are told that  

     M  = \frac{ \frac{m v^2}{r} }{\frac{ mG}{r^2 } }

So simplifying we have

    M  =    \frac{m v^2}{r} *  \frac{r^2 }{ mG }

    M  =  \frac{v^2 r}{G}

Thus the simplified formula is M  =  \frac{v^2 r}{G}

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The measure of one of the small angles of a right triangle is 45 less than twice the measure of the other small angle. Find the
astra-53 [7]

Answer:

The other two small angles are 45° each

Explanation:

Given data in the problem:

The triangle is a right triangle

thus,

one of the angle is 90°

now,

let the other two angles be x and y

thus,

it is given that:

x = 2y - 45°

also in a triangle

sum of all the angles = 180°

thus,

x + y + 90° = 180°

or

x + y = 90°

now, substituting the  value of x from the above relation between x and y, we get

2y - 45° + y = 90°

or

3y = 135°

or

y = 45°

also,

x = 2y - 45°

or

x = 2 × (45°) - 45°

or

x = 45°

hence, <u>the other two small angles are 45° each</u>

4 0
2 years ago
A worker wants to turn over a uniform 1110-N rectangular crate by pulling at 53.0 ∘ on one of its vertical sides (the figure (Fi
tekilochka [14]
This problem has three questions I believe:

> How hard does the floor push on the crate?

<span>We have to find the net vertical (normal) Fn force which results from Fp and Fg. 
We know that the normal component of Fg is just Fg, which is equal to as 1110N. 
From the geometry, the normal component of Fp can be calculated: 
Fpn = Fp * cos(θp) 
= 1016.31 N * cos(53) 
= 611.63 N 

The total normal force Fn then is: 
Fn = Fg + Fpn 
= 1110 + 611.63
= 1721.63 N</span>

 

> Find the friction force on the crate

<span>We have to look for the net horizontal force Fh which results from Fp and Fg. Since Fg is a normal force entirely,  so we can say that the horizontal component is zero: 

Fh = Fph + Fgh 
= (Fp * sin(θp)) + 0 
= 1016.31 N * sin(53) 
= 811.66 N</span>

 

> What is the minimum coefficient of static friction needed to prevent the crate from slipping on the floor?

We just need to compute the ratio Fh to Fn to get the minimum μs.

 

μs = Fh / Fn

= 811.66 N / 1721.63 N

<span>= 0.47</span>

8 0
2 years ago
A CCD has a greatest possible pixel value of 4095. what is the bit level of this CCD?
Shtirlitz [24]
<span>Bit level for a CCD (Charged coupled device) with a greatest possible pixel value of 4095:The relationship between the bit level and pixel value is given as:pixel value = 2^bit level.Most charged coupled devices (CCDs) have 8-bit, 16-bit, 32-bit levels.Using simple mathematics, we can see that 2^12 = 4096.Since the maximum number of pixels is 4095, the bit level is 12., i.e. the CCD has 12-bit level.</span>
8 0
2 years ago
Which formula is used to find fluctuation of the shape of body
Sladkaya [172]

Answer:

varn=n1+1ehvkT–1

Explanation:

This is Einstein's equation.

5 0
2 years ago
1. A particular lever is 90.0% efficient. If 50.0 J of work are done on the lever, then how much work does the lever do on its l
laila [671]

Answer:

Explanation:

Using the efficiency formula;

Efficiency = Work done by the machine (output)/work done on the machine (input) ×100%

Efficiency =w/50 ×100

90 = 100w/50

Cross multiply

90×50 = 100W

4500 = 100W

W = 4500/100

W = 45Joules

Hence the lever does 45Joules of work on its load

2) Mechanical Advantage= Load/Effort

Given

MA = 4

Load = 500N

4 = 500/Effort

Effort = 500/4

Effort =125N

Hence the effort required to lift the load is 125N

8 0
1 year ago
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