A balloon tied up with a wooden piece is moving upward with velocity of 15m/s. At a height of 300m above the ground, the wooden
1 answer:
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Answer:
275 kPa
Explanation:
mass of the gas=m=1.5 kg
initial volume if the gas=V₁=0.04 m³
initial pressure of the gas= P₁=550 kPa
as the condition is given final volume is double the initial volume
V₂=final volume
V₂=2 V₁
As the temperature is constant
T₁=T₂=T
=
putting the values in the equation.
=
P₂=
P₂=
P₂=275 kPa
So the final pressure of the gas is 275 kPa.
Answer:
T=C*P*V
Explanation:
It is said that a variable - let's call 'y' -, is proportional to another - let's call it 'x' - if x and y are multiplicatively connected to a constant 'C'. It means that their product (x*y) can be always equaled to the constant 'C' or their division () can be always equaled to 'C'. The first case is the case of the inverse proportionality: It is said that x and y are inversely proportional if
The second case is the case of the direct proportionality: It is said that x and y are directly proportional if
: x is directly proportional to y.
or
: y is directly proportional to x.
Always that any text does not specify about directly or inversely proportionality, it is assumed to mean directly automatically.
For our case, we are said that the temperature T is proportional to the pressure P and the volume V (we assume that it means directly); it is a double proportionality but follows the same rules:
If T were just proportional to P, we would have:
If T were just proportional to V, we would have:
As T is proportional to both P and V, the right equation is:
In order to isolate the temperature, let's multiply (P*V) at each side of the equation:
The intensity is defined as the ratio between the power emitted by the source and the area through which the power is calculated:
(1)
where
P is the power
A is the area
In our problem, the intensity is
. At a distance of r=6.0 m from the source, the area intercepted by the radiation (which propagates in all directions) is equal to the area of a sphere of radius r, so:
And so if we re-arrange (1) we find the power emitted by the source:
where
P is the power
A is the area
In our problem, the intensity is
And so if we re-arrange (1) we find the power emitted by the source: