All categories

2 years ago

If you apply 100.0 N of force to lift an object with a single, fixed pulley, then what is the resistive force?

1 answer:

6 0

If you apply 100.0 N of force to lift an object with a single, fixed pulley, then the resistive force is also equivalent to 100 Newtons of force. Since the weight of the object was not mentioned, it is assumed that it has already been taken into account in the 100 N value of force. This follows Newton's law of motion of equal action and reaction.

You might be interested in

A cement factory emits 900 kilograms of CO2 to produce 1,000 kilograms of cement. A fully grown tree removes six kilograms of CO

Dmitriy789 [7]

<h3>Answer;</h3>

To make the factory carbon neutral, the owners need to grow 15000 trees over an area of land measuring 75 acres

<h3>Explanation and solution;</h3>

From the information;

900 kg CO2 = 1000 kg Cement

1 tree = 6 kg CO2

1 acre = 200 trees

100000 kg Cement will require;

=(900 × 100000)/1000

= 90,000 kg of CO2

But 1 tree = 6 kg of CO2

Number of trees = 90,000/6

= 15,000 trees

But, 1 acre = 200 trees

Number of acres = 15,000/200

= 75 acres of land

Therefore;

To make the factory carbon neutral, the owners need to grow 15000 trees over an area of land measuring 75 acres

6 0

2 years ago

Read 2 more answers

A bee wants to fly to a flower located due North of the hive on a windy day. The wind blows from East to West at speed 6.68 m/s.

Aleonysh [2.5K]

Answer: $53.31\°$ East of North

Explanation:

We have the following data:

Speed of the wind from East to West: $6.68 m/s$

Speed of the bee relative to the air: $8.33 m/s$

If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the Speed of the wind from East to West (in the horintal part) and the speed due North relative to the ground (in the vertical part).

Now, we need to find the direction the bee should fly directly to the flower (due North):

$sin \theta=\frac{Windspeed-from-East-to-West}{Speed-bee-relative-to-air}$

$sin \theta=\frac{6.68 m/s}{8.33 m/s}$

Clearing $\theta$ :

$\theta=sin^{-1} (\frac{6.68 m/s}{8.33 m/s})$

$\theta=53.31\°$

6 0

2 years ago

The price of coffee fell sharply last month, while the quantity sold remained the same. Five people suggest various explanations

miss Akunina [59]

Answer:

France. True Supply increased and demand did not adapt

Explanation:

If the price of coffee decreases it may be due to two causes

- Increase of the offer

- decrease in demand

- both simultaneously.

Let's examine the statement. They tell us that the amount sold remained constant, so there is no decrease in demand, therefore the only cause may be the increase in supply.

Let's check the answers

Antonio False. The demand is constant.

Carolina. False. The demand is constant.

Dmitri False. The demand is constant.

France. True Supply increased and demand did not adapt

Jake. False. Demand did not adapt to the increase in supply

7 0

2 years ago

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction

Vaselesa [24]

Answer:

H=1020.12m

Explanation:

From a balance of energy:

$\frac{m*Vo^2}{2} -mg*H=-Ff*d$ where H is the height it reached, d is the distance it traveled along the ramp and Ff = μk*N.

The relation between H and d is given by:

H = d*sin(30) Replace this into our previous equation:

$\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*N*d$

From a sum of forces:

N -mg*cos(30) = 0 => N = mg*cos(30) Replacing this:

$\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*mg*cos(30)*d$ Now we can solve for d:

d = 2040.23m

Thus H = 1020.12m

6 0

1 year ago

Read 2 more answers

The Slowing Earth The Earth's rate of rotation is constantly decreasing, causing the day to increase in duration. In the year 20

NNADVOKAT [17]

Answer:

The average angular acceleration of the Earth, α = 6.152 X 10⁻²⁰ rad/s²

Explanation:

Given data,

The period of 365 rotation of Earth in 2006, T₁ = 365 days, 0.840 sec

= 3.1536 x 10⁷ +0.840

= 31536000.84 s

The period of 365 rotation of Earth in 2006, T₀ = 365 days

= 31536000 s

Therefore, time period of one rotation on 2006, Tₐ = 31536000.84/365

= 86400.0023 s

The time period of rotation is given by the formula,

Tₐ = 2π /ωₐ

ωₐ = 2π / Tₐ

Substituting the values,

ωₐ = 2π / 365.046306

= 7.272205023 x 10⁻⁵ rad/s

Therefore, the time period of one rotation on 1906, Tₓ = 31536000/365

= 86400 s

Time period of rotation,

Tₓ = 2π /ωₓ

ωₓ = 2π / T

= 2π /86400

= 7.272205217 x 10⁻⁵ rad/s

The average angular acceleration

α = (ωₓ - ωₐ) / T₁

= (7.272205217 x 10⁻⁵ - 7.272205023 x 10⁻⁵) / 31536000.84

α = 6.152 X 10⁻²⁰ rad/s²

Hence the average angular acceleration of the Earth, α = 6.152 X 10⁻²⁰ rad/s²

3 0

2 years ago