Question

A source charge generates an electric field of 4286 N/C at a distance of 2.5 m. What is the magnitude of the source charge?

Answer 1

The Answer is 3.0uc. I took the quiz.

Answer 2

Answer : Charge, $q=3.0\ \muC$

Explanation :

It is given that :

Electric field, $E=4286\ N/C$

Distance, $r=2.5\ m$

We know that the electric field at any point is given by :

$E=k\dfrac{q}{r^2}$

k is the electrostatic constant.

q is the electric charge

r is the distance.

$q=\dfrac{E\times r^2}{k}$

$q=\dfrac{4286\ N/C\times (2.5\ m)^2}{9\times 10^9\ Nm^2/C^2}$

$q=0.0000029\ C$

$q=2.9\ \mu C$

or

$q=3.0\ \mu C$

The correct option is (b).

Hence, this is the required solution.