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liberstina [14]
1 year ago
15

5. A 1-kg car and a 2-kg car are both released from the top of the same hill and roll down a frictionless track. At the bottom o

f the hill, which car will have the greater
speed? Which car will have the greater Kinetic energy?

O A The 1-kg car will have greater speed, and the 2-kg car will have greater kinetic energy

OB. The 2 kg car car will have greater speed, and the 7-kg car will have greater kinetic energy

OC. The cars will have equal speeds and equal kinetic energies.

OD. The cars will have equal speeds and the 2 kg car will have greater kinetic energy
Physics
1 answer:
grigory [225]1 year ago
7 0

The cars will have equal speeds and the 2 kg car will have greater kinetic energy.

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On a snowy day, when the coefficient of friction μs between a car’s tires and the road is 0.50, the maximum speed that the car c
Nana76 [90]

Answer:

28.1 mph

Explanation:

The force of friction acting on the car provides the centripetal force that keeps the car in circular motion around the curve, so we can write:

F=\mu mg = m \frac{v^2}{r} (1)

where

\mu is the coefficient of friction

m is the mass of the car

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v is the maximum speed of the car

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On the snowy day,

\mu=0.50\\v = 20 mph = 8.9 m/s

So the radius of the curve is

r=\frac{v^2}{\mu g}=\frac{(8.9)^2}{(0.50)(9.8)}=16.1 m

Now we can use this value and re-arrange again the eq. (1) to find the maximum speed of the car on a sunny day, when \mu=1.0. We find:

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7 0
1 year ago
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A 1500-kg car locks its brakes and skids to a stop on a slippery horizontal road, leaving skid marks that are 15 m long. How muc
Harman [31]

Answer:

E=88200\ J

Explanation:

Given:

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<u>So, the energy dissipated during the skidding of car:</u>

<em>Frictional force:</em>

f=\mu_k.N

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<em>Now from the work-energy equivalence:</em>

E=f.d

E=5880\times 15

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Answer:

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four children pull on the same stuffed toy at the same time , yet there is no net force on the toy.how is this possible?
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