Answer:
3/7 ω
Explanation:
Initial momentum = final momentum
I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet
-Iω + 6Iω - 2Iω = 7I ωnet
3Iω = 7I ωnet
ωnet = 3/7 ω
The final angular velocity will be 3/7 ω counterclockwise.
Answer:
1.32.225 N/C, direction is away from the point charge
2. 8.972*10^-12 C
3. the field is directed away from the axon
Explanation:
The electric field can be calculated as shown below:
E = k*|q|/r^2
Where:
E = electric field; k = 8.98755*10^9 N*m^2/C^2; r = distance between the measured field and point charge = 0.05 m; q = the point charge
For 0.100 m of the axon, the value of q is:
q = (5.6*10^11)*(+e)*(0.001)
+e = charge of an electron = 1.60217*10^-19 C
Thus:
q = (5.6*10^11)*(1.60217*10^-19)*(0.0001) = 8.972*10^-12 C
Therefore:
E = (8.98755*10^9)*(8.972*10^-12)/0.05^2 = 32.255 N/C
A positive point charge always produce an electric field that is directed away from the field while a negative point charge produces an electric field that is directed toward the field
In order to overcome an object’s inertia (resistance to change), it must be acted upon by an unbalanced force, so the answer to the problem is letter C.
Answer:
dont you have to times it
Explanation:
