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Anni [7]
2 years ago
6

A migrating salmon heads in the direction n 45° e, swimming at 2 mi/h relative to the water. the prevailing ocean currents flow

due east at 4 mi/h. find the true velocity of the fish as a vector. (assume that the i vector points east, and the j vector points north.)
Physics
1 answer:
Sophie [7]2 years ago
5 0
Calculate for the x and y-components of the velocities involved in this item.

 2 mi/h (45° east)
  x-component = (2 mi/h)(sin 45°)
                     = 1.41 mi/h
  y-component = (2 mil/h)(cos 45°)
                     = 1.41 mi/h

4 mi/h (east)
  x-component = 4 mi/h
  y-component = 0 mi/h

Adding up the corresponding components:
     x-component = 5.4142 mi/h

     y-component = 1.4142 mi/h

Calculating for the resultant,
        R = sqrt ((x²) + (y²))
   
        R = sqrt ((5.4142 mi/h)² + (1.4142 mi/h)²)
             R = 5.60 mi/h

Answer: 5.6 mi/h
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Water runs into a fountain, filling all the pipes, at a steady rate of 0.750 m3>s. (a) How fast will it shoot out of a hole 4
kati45 [8]

Answer:

velocity  = 472 m/s

velocity = 52.4 m/s

Explanation:

given data

steady rate = 0.750 m³/s

diameter = 4.50 cm

solution

we use here flow rate formula that is

flow rate = Area × velocity .............1

0.750 = \frac{\pi }{4} × (4.50×10^{-2})²  × velocity

solve it we get

velocity  = 472 m/s

and

when it 3 time diameter

put valuer in equation 1

0.750 = \frac{\pi }{4} × 3 ×  (4.50×10^{-2})²  × velocity

velocity = 52.4 m/s

5 0
2 years ago
A child is sliding a toy block (with mass = m) down a ramp. The coefficient of static friction between the block and the ramp is
tiny-mole [99]

Answer:

F=mg(sin(\theta )-0.25 cos(\theta ))

Explanation:

The free body diagram of the block on the slide is shown in the below figure

Since the block is in equilibrium we apply equations of statics to compute the necessary unknown forces

N is the reaction force between the block and the slide

For equilibrium along x-axis we have

\sum F_{x}=0\\\\mgsin(\theta )-\mu N-F=0\\\therefore F=mgsin(\theta)-\mu N......(\alpha )\\Similarly\\\sum F_{y}=0\\\\N-mgcos(\theta )=0\\\therefore N=mgcos(\theta ).......(\beta )\\\\

Using value of N from equation β in α we get value of force as

F=mg(sin(\theta )-\mu cos(\theta ))

Applying values we get

F=mg(sin(\theta )-0.25 cos(\theta ))

8 0
2 years ago
Read 2 more answers
A certain part of a flat screen TV has a thickness of 150 nanometers. How<br> many meters is this?
Bess [88]

Answer:

1.5e-7 meters

.00000015 meters

Explanation:

.000000001 meters = 1 nanometer. Multiply that by 150 and an answer is there.

5 0
2 years ago
Suppose the truck that’s transporting the box In Example 6.10 (p. 150) is driving at a constant speed and then brakes and slows
Scorpion4ik [409]

Answer:

Friction acts in the opposite direction to the motion of the truck and box.

Explanation:

Let's first review the problem.

A moving truck applies the brakes, and a box on it does not slip.

Now when the truck is applying brakes, only it itself is being slowed down. Since the box is slowing down with the truck, we can conclude that it is friction that slows it down.

The box in the question tries to maintains its velocity forward when the brakes are applied. We can think of this as the box exerting a positive force relative to the truck when the brakes are applied. When we imagine this, we can also figure out where the static friction will act to stop this positive force. Friction will act in the negative direction. Or in other words, friction will act in the opposite direction to the motion of the truck and box. This explains why the box slows down with the truck, as friction acts to stop its motion.

5 0
1 year ago
The angular width of localizers varies between ______ and ______ degrees in order to provide a signal width of approximately 700
natali 33 [55]

Answer: 10 and 35 degrees

Explanation: Localizers width below 10 degree and 35 degree signal arc is unreliable and considered unusable for navigation and as a result, aircrafts may loose alignment

5 0
2 years ago
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