Answer:
Explanation:
Where;
a = acceleration
V2 = final velocity
V1 = initial velocity
t = time
If John runs 1.0 m/s first, we assume this is V1. He accelerates to 1.6 m/s; this is V2.
A car enters a 300-m radius horizontal curve on a rainy day when the coefficient of static friction between its tires and the ro
1 answer:
To solve this problem it is necessary to take into account the concepts related to Centripetal Force and Friction Force.
In the case of the centripetal force, we know that it is defined as
Where,
m=mass
v= velocity
r= Radius
In the case of the Force of Friction we have to,
Where,
Friction Constant
m= mass
g= gravity
According to the information given, the centripetal force must be less than or equal to the friction force to stay on the road, in this way
Re-arrange to find the velocity,
Therefore la velocidad del carro debe ser igual o menor a 42m/s para mantenerse en el camino
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Answer: 1 m/s
Explanation:
We have an object whose position is given by a vector, where the components X and Y are identified by the unit vectors
and
(where each unit vector is defined to have a magnitude of exactly one):
On the other hand, velocity is defined as the variation of the position in time:
This means we have to derive :
This is the velocity vector
And when the velocity vector is:
This is the velocity vector at 2 seconds
However, the solution is not complete yet, we have to find the module of this velocity vector, which is the speed :
Finally:
This is the speed of the object at 2 seconds