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sergij07 [2.7K]
2 years ago
13

One beam of electrons moves at right angles to a magnetic field. the force on these electrons is 4.9 x 10-14 newtons. a second b

eam travels at the same speed, but at a 30° angle with the magnetic field. what force is on these electrons?
Physics
1 answer:
diamong [38]2 years ago
7 0
Below are the choices that can be found elsewhere:

A. (4.9 × 10-14 newtons) · tan(30°) 
<span>B. (4.9 × 10-14 newtons) · sin(30°) </span>
<span>C. (4.9 × 10-14 newtons) · cos(30°) </span>
<span>D. (4.9 × 10-14 newtons) · arctan(30°) </span>
<span>E. (4.9 × 10-14 newtons) · arccos(30°)
</span>
<span>Force is proportional to the angle made by the velocity with respect to the magnetic field. It is maximum when velocity is perpendicular to the magnetic field and minimum when the velocity is parallel to the magnetic field. It is proportional to sin of the angle. In this problem it will be proportional to sin(30)</span>
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Answer:

The correct dose = 1454.54 mg

and The jnfusion rate = 41.67 gitt/hr

Explanation: the correct dose will be 50mg/kg × kg/2.2 × 64lb

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infusion rate will be

10 gtts/ml × 50mg/6 × 30/60

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5 0
2 years ago
A 1.0-m-long copper wire of diameter 0.10 cm carries a current of 50.0 A to the east. Suppose we apply to this wire a magnetic f
Setler79 [48]

Answer:

The classification of that same issue in question is characterized below.

Explanation:

The given values are:

Current, I = 50.0 A

Diameter, d = 0.10 cm

(a)...

As we know,

⇒  Magnetic force = Copper wire's weight

So,

⇒   B\times I\times L=M\times g

On putting the estimated values, we get

⇒  B\times 50\times 1=7.037\times 10^{-3}\times 9.81

⇒  50B=69.03297\times 10^{-3}

⇒  B=1.38\times 10^{-3} \ T

(b)...

As we know,

⇒  m=\delta\times L\times \frac{\pi \ d^2}{4}

⇒      =8960\times 1\times \frac{\pi \ (0.001)^2}{4}

⇒      =2240\times \pi \ 0.000001

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7 0
2 years ago
For a particular reaction, the change in enthalpy is 51kJmole and the activation energy is 109kJmole. Which of the following cou
Ronch [10]

Answer

given,

change in enthalpy = 51 kJ/mole

change in activation energy = 109 kJ/mole

when a reaction is catalysed change in enthalpy between the product and the reactant does not change it remain constant.

where as activation energy of the product and the reactant decreases.

example:

ΔH = 51 kJ/mole

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2 years ago
A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 2.7 s later with an init
Darina [25.2K]

Answer:4.05 s

Explanation:

Given

First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s

Both hit the ground at the same time

Let h be the height of cliff and it reaches after time t

h=\frac{gt^2}{2}

For second stone

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26.46t-35.721-52.92t+142.884=0

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Answer:

A,C,E

Explanation:

5 0
1 year ago
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