Answer:
When extra energy is added
Explanation:
When the ball is released from rest and swings back towards your face, it will only pass closer to the end of the nose as per the initial conditions. However, when extra energy is added to the ball, it strikes the nose since its velocity and heights are increased. Therefore, the only condition under which the ball hits your nose is when extra energy is added to the system.
Answer:
see below for the truth table
Explanation:
<u>Truth Table</u>
As we will see from the description of operation, any input low causes the output to be high. This is the logic of a NAND gate. The truth table is attached.
<u>Working Principle</u>
Pulling any of A, B, or C low will saturate transistor Q1, depriving Q2 of any base current, cutting it off. Then Q5 is also deprived of base current and is cut off. Meanwhile, the current through R2 supplies base current to Q4, allowing it to pull the output high.
If all of A, B, and C are high (or open), base current is supplied to Q2 through the base-collector junction of Q1. Then Q2 saturates, supplying base current to Q3. Diode D1 ensures that the voltage across Q2 will be insufficient to supply any base current to Q4, so it stays cut off.
Answer:
r = 0.114 m
Explanation:
To find the speed of the proton, from conservation of energy, we know that
KE = PE
Thus, we have;
(1/2)mv² = qV
Where;
V is potential difference = 1kv = 1000V
q is charge on proton which has a value of 1.6 x 10^(-19) C
m is mass of proton with a constant value of 1.67 x 10^(-27) kg
Let's make the velocity v the subject;
v =√(2qV/m)
v = √(2•1.6 x 10^(-19)•1000)/(1.67 x 10^(-27))
v = 4.377 x 10^(5) m/s
Now to calculate the radius of the circular motion of charge we know that;
F = mv²/r = qvB
Thus, mv²/r = qvB
Divide both sides by v;
mv/r = qB
Thus, r = mv/qB
Value of B from question is 0.04T
Thus,
r = (1.67 x 10^(-27) x 4.377 x 10^(5))/(1.6 x 10^(-19) x 0.04)
r = 0.114 m
r = 8.76 m
Answer:
Explanation:
Given
time taken to complete the circle=7.9 s
radius of circle(r)=15 m
velocity of rider is given by 

Let us suppose T is the tension in the chain and
is the angle which chain makes with vertical
Therefore 
--2
Divide 1 & 2 we get



Answer:
1.056 x 10⁷ lb-ft
Explanation:
v = Speed of the bike = 20 mph
t = time of travel = 2 h
d = distance traveled by cyclist
Distance traveled by cyclist is given as
d = v t
d = (20) (2)
d = 40 miles
We know that, 1 mile = 5280 ft
d = 40 (5280) ft
d = 211200 ft
F = force applied by cyclist = 50 lb
W = work done by cyclist
Work done by cyclist is given as
W = F d
W = (50) (211200)
W = 1.056 x 10⁷ lb-ft