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irakobra [83]
2 years ago
15

A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizonta

l direction with a variable speed and from a variable vertical position and a fixed horizontal position x = 0. The robot is calibrated by adjusting the speed at which the sphere is launched and the height of the robot's sphere launcher. Depending on where the spheres land on the ground, students earn points based on the accuracy of the robot. The robot is calibrated so that when the spheres are launched from a vertical position y = H and speed vo, they consistently land on the ground on a target that is at a position x = D. Positive directions for vector quantities are indicated in the figure. a) On the axes below, sketch the graphs of the horizontal and vertical components of the sphere's velocity v as a function of time t between t = 0, when the sphere is launched and t =T. when the sphere hits the target. Label t =T for the horizontal component of the sphere's velocity and the vertical component of the sphere's velocity,​
Physics
1 answer:
Dvinal [7]2 years ago
8 0
Nobody will do that for 5 points loll
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5.2x10^-25

Explanation:

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Which best describes what forms in nuclear fission?A. two smaller, more stable nucleiB. two larger, less stable nucleiC. one sma
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A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
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Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

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The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

Gravitational force on an object = mg

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2 years ago
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Johnny was playing baseball with his friends and they noticed a bolt of lightning. They heard thunder seven seconds later. How f
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2 years ago
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Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
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Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value is F_j  =  550\ N

Explanation:

From the question we are told that

   The length of the stretcher is  d =  2.0 \  m

    The weight of the stretcher is W  =  100 \  N

    The weight for Wayne is  W_w =  800 \ N

     The distance of  center of gravity for Wayne from Chris is c_w = 75 cm  =  0.75 \ m

Generally taking moment about the first end where Chris is

         F_j *  d              => upward moment

Here F_j is the force applied by Jamie

Generally  taking moment about the second end where Jamie is

      W *  ( \frac{d}{2} ) +  W_w * (d - c_w)      => downward moment

Generally at equilibrium , the upward moment is equal to the downward moment

     F_j *  d = W *  ( \frac{d}{2} ) +  W_w * (d - c_w)

=>   F_j *  2  = 100 *  ( \frac{ 2}{2} ) +  800 * (2 - 0.75)

=>    F_j  =  550\ N

3 0
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