Answer:
<h2>9.375Nm</h2>
Explanation:
The formula for calculating torque τ = Frsin∅ where;
F = applied force (in newton)
r = radius (in metres)
∅ = angle that the force made with the bar.
Given F= 25N, r = 0.75m and ∅ = 30°
torque on the bar τ = 25*0.75*sin30°
τ = 25*0.75*0.5
τ = 9.375Nm
The torque on the bar is 9.375Nm
I think it would be B because it is matter, since it has atoms, and it contains subatomic particles, which are smaller than atoms
Explanation:
It is given that,
Mass of Madeleine, 
Initial speed of Madeleine, 
(due east)
Final speed of Madeleine, 
(due west)
Mass of Buffy, 
Final speed of Buffy, 
(due east)
Let 
is the Buffy's velocity just before the collision. Using the conservation of linear momentum as :
So, the initial speed of the Buffy just before the collision is 7.13 m/s and it is moving due west. Hence, this is the required solution.
Answer:
A) 0.33 m/s
Explanation:
The standard form of a transverse wave is given by
y
=
a cos
(
ω
t
−
kx
) , k
= 2
π / λ
Amplitude, a
= 0.002 m
Wavenumber (k)=47.12 and wavelength (
λ
) = 0.133
m
Time period(T)=0.0385 s and angular frequency (
ω
) = 52
π rad/s
Maximum speed of the string is given by aw
Therefore ; max. speed = 0.002 x 52 π = 0.327 m/s
Answer:
T = 686.7N
Explanation:
For this exercise we will use Newton's second law in this case there is no acceleration,
∑ F = ma
T -W = 0
The gymnast's weight is
W = mg
We clear and calculate the tension
T = mg
T = 70 9.81
T = 686.7N
