Object A with a mass of 500 kilograms hits stationary object B with a mass of 920 kilograms. If the collision is elastic, what h
1 answer:
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Answer:
the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm
Explanation:
The change in volume of glycerin when the ice cube is placed on the surface of the glycerin can be represented as:
Given that ;
the mass of the ice cube (m) = 0.11 kg = 0.110 × 10³ g
density of the glycerine () = 1.260 kg/L = 1.260 g/cm³
Then:
V =
V =
V = 0.0873 L
Now;Initially the volume of the glycerin before the ice cube starts to melt is:
However; the volume of the water produced by the 0.11 kg ice cube =
The expression for change in the volume of glycerin after the ice cube starts to melt is as follows:
replacing with
; we have:
The overall total change in the volume of the glycerin is illustrated as:
Now; from the foregoing ; lets replace the respective value of and
in the above equation ; we have;
The formula usually known to be the volume of a cylinder is :
For the question ; we will have:
making h the subject of the formula ; we have:
replacing 0.0227 L for and the given value of radius which is = 3.70 cm; we have:
Thus ; the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm
Answer:
Option B, 93 cm
Explanation:
An diagram of the seed's motion is attached to this solution.
This is very close to a projectile motion question. And the quantity to be calculated, how far along the grant a seed released would travel is called the Range.
And this would be obtained from the equations of motion,
First of, the height of the plant is related to some quantities of the motion with this relation.
H = u(y) t + 0.5g(t^2)
U(y) = initial vertical component of velocity = 0 m/s, H = height at which motion began, = 20cm = 0.2 m
That means t = √(2H/g)
The horizontal distance covered, R,
R = u(x) t + 0.5g(t^2) = u(x) t (the second part of the equation goes to zero as the vertical component of the acceleration of this motion is 0)
(substituting the t = √(2H/g) derived from above
R = u(x) √(2H/g)
Where u(x) = the initial horizontal component of the bomb's velocity = maximum initial speed, that is, 4.6 m/s, H = vertical height at which the seed was released = 20 cm = 0.2 m, g = acceleration due to gravity = 9.8 m/s2
R = 4.6 √(2×0.2/9.8) = 0.929 m = 0.93 m = 93 cm. Option B.
QED!
