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wariber [46]
2 years ago
14

Object A with a mass of 500 kilograms hits stationary object B with a mass of 920 kilograms. If the collision is elastic, what h

appens after the collision?
A)Both object A and object B move forward but with different velocities.

B)Object A and object B stick together and move forward together.

C)Object B moves forward, but object A moves backward.

D)Object A stops and object B moves forward.
Physics
1 answer:
Vika [28.1K]2 years ago
5 0
In elastic collision, both the kinetic energy and momentum are conserved. Conservation means that both the kinetic energy and momentum will have the same values before and after elastic collision.

<span>As the object A has low mass than object B. Hence upon collision, object B moves forward, while object A will move backward. So option "C" is correct. </span>

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Derive an algebraic equation for the vertical force that the bench exerts on the book at the lowest point of the circular path i
fiasKO [112]

Answer:

The algebraic equation is:

F_{v} =\frac{m_{b}v_{b}^{2}   }{R} -m_{b} g

Explanation:

Given information:

mb = book's mass

vb = tangential speed

R = radius of the path

Question: Derive an algebraic equation for the vertical force, Fv = ?

To derive the equation, we need to draw a force diagram for this case, please, see the attached diagram. As you can see, there are three types of forces acting on the system. Two up and one of the weight acting down. Therefore, the algebraic equation is as follows:

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2 years ago
You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves along a frictionless track. however, af
djyliett [7]
I attached the missing picture.
We can figure this one out using the law of conservation of energy.
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W_f=F_f\cdot L
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mgh_1+\frac{mv_1^2}{2}- F_fL
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B: mgh_2+\frac{mv_2}{2}
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mgh_2+\frac{mv_2}{2}=mgh_1+\frac{mv_1^2}{2}- F_fL
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4 0
2 years ago
Read 2 more answers
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Answer:

8.67807 N

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\rho_{se} = Density of seawater = 1030 kg/m³

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\rho_{sh} = Density of shark = 1040 kg/m³

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Net force on the fin is (seawater)

F_n=mg-V_s\rho_{se}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{se}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1030\times 9.81\\\Rightarrow F_n=8.67807\ N

The lift force required in seawater is 8.67807 N

Net force on the fin is (freshwater)

F_n=mg-V_s\rho_{f}g\\\Rightarrow F_n=mg-\frac{m}{\rho_{sh}}\rho_{f}g\\\Rightarrow F_n=92\times 9.81-\frac{92}{1040}\times 1000\times 9.81\\\Rightarrow F_n=34.7123\ N

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6 0
2 years ago
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nekit [7.7K]

Answer:

It is A

Explanation:

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Setler [38]

Answer:

Explanation:

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To help you, check out the picture!

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