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svp [43]
1 year ago
13

Fiona and her twin sister April are enjoying the bumper cars at an amusement park. Fiona drives her car toward her sisters and t

he two cars collide. Before the collision, Fiona was moving with a speed of 3 m/s and April was moving with a speed of 1 m/s. After the collision, Fiona is moving with a speed of 1 m/s and April is moving with a speed of 3 m/s. If Fiona and her bumper car have a combined mass of 80 kg, what is the combined mass of April and her bumper car?
M2 = ? kg
Physics
1 answer:
vlabodo [156]1 year ago
5 0

The mass of April and her bumper car is 80 kg

Explanation:

This problem can be solved by using the law of conservation of momentum.

In fact, the total momentum of the system must be conserved before and after the collision, so we have:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 80 kg is the mass of Fiona+her bumper

u_1 = 3 m/s is the initial velocity of Fiona (we take her direction as positive direction)

v_1 = -1 m/s is the final velocity of Fiona (she rebounds back)

m_2 is the mass of April+her bumper

u_2 = - 1 m/s is the initial velocity of April (in the opposite direction)

v_2 = 3 m/s is the final velocity of April

Re-arranging the equation, we can find the mass of April+bumper:

m_2 = \frac{m_1 u_1 - m_1 v_1}{v_2-u_2}=\frac{(80)(3)-(80)(-1)}{3-(-1)}=80 kg

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

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1. Each year at a college, there is a tradition of having a hoop rolling competition. Alex rolls his 0.350 kg hoop down the cour
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Question 1:

Answer:

The moment of inertia of Alex's rolling hoop is 0.197 kg \cdot cm^2

Explanation:

<u>Given</u>:

Mass of the hoop = 0.350 g

Radius of the hoop = 75.0 cm

<u>To Find:</u>

The moment of inertia of Alex's rolling hoop = ?

<u>Solution</u><u>:</u>

The moment of inertia  = mr^2

where

m is the mass

r is the radius

Converting cm to m, we get

75.0 cm = 0.75 m

Now substituting the values,

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=> moment of inertia  = (0.350)(0.5625)

=> moment of inertia  = (0.197)

Question 2:

Answer:

The combined angular momentum of the masses is 1.76 kg m^2 s^{-1}

If she pulls her arms in to 0.12 m, her new linear speed  is  18.33 m/s^2

Explanation:

Given:

Mass  = 2.0 kg

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Velocity =  1.2 m/s

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b. If she pulls her arms in to 0.12 m, what is her new linear speed

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v_2 = \frac{1.76}{0.096}

v_2 = 18.33 m/s^2

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