Answer:
<h2>Center of gravity of the system of all masses is 105 cm from the left end of the rod</h2>
Explanation:
Let the position of Left end of the rod is our reference
So here we will have










so we will have



Answer:
The banking angle of the road is 16.38 degrees.
Explanation:
Given:
Radius of the roadway on curve, R = 50 m
velocity of the moving car, V = 12 m/s
The banking angle can be calculated by using the formula below:
If there's no frictional force, then net force is equal to centripetal force.
MgTanΦ = (MV^2)/ R
TanΦ = V^2 / gR
Where;
Φ is the banking angle
g is acceleration due to gravity
TanΦ = (12 x 12) / (9.8 x 50)
TanΦ = 0.2939
Φ = arctan (0.2939)
Φ = 16.38 degrees
Therefore, the banking angle of the road is 16.38 degrees.
V = I * R
Where V is the voltage, I is the current and R is the resistance. Using Ohm's law, you require resistance to find the current through the wire. Technically, if the wire has a resistance of 0, you will get infinite current. But this isn't possible. Maybe the negligible resistance refers to the battery's internal resistance - not the wire's resistance.
Work done by a given force is given by

here on sled two forces will do work
1. Applied force by Max
2. Frictional force due to ground
Now by force diagram of sled we can see the angle of force and displacement
work done by Max = 

Now similarly work done by frictional force



Now total work done on sled


Answer:
2.93 A
Explanation:
From Ohm's law V = IR where V = voltage = 12 V, I = current = ? and R = resistance = 4.1 Ω.
So, the current in each quadraphonic stereo circuit is I = V/R = 12 V/4.1 Ω = 2.93 A