All categories

2 years ago

An average human weighs about 600 N

Physics

1 answer:

NemiM [27]2 years ago

4 0

Answer:

The distance between them, x = 5809.47 m

Explanation:

Given,

The average weight of a human, w = 600 N

The charge carried by the humans, q = 1.5 C

If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,

$F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}$

Where,

$\frac{1}{4\pi\epsilon_{0}}$ = 9 x 10⁹ N m² C⁻²

Therefore

x² = 9 x 10⁹ X 1.5² / 600

= 33750000

x = 5809.46 m

Hence, the distance between the humans should be, x = 5809.47 m

You might be interested in

A particle is in uniform circular motion. Assume a standard rtz coordinate system. If you deconstruct the net force acting on th

Kitty [74]

Answer:

a) One

Explanation:

In a uniform circular motion there must be a force acting to keep it in the circular track. This force can either be centripetal or a centrifugal force.

According to the Newton's first law of motion a particle continues to be in state of rest or in uniform motion until acted upon by an external force.

Here the term uniform motion need to be understood which refers to the uniform velocity of the particle in accordance to the vector laws.

3 0

2 years ago

A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds. What is its average

frez [133]

(u) = 20 m/s
(v) = 0 m/s
 (t) = 4 s

0 = 20 + a(4)

4 x a = -20

so, the answer is -5 m/s^2. or -5 meter per second

8 0

2 years ago

Read 2 more answers

A 25-mm-diameter uniform steel shaft is 600 mm long between bearings. (7-33) (9 Pts) A. Find the lowest critical speed of the sh

Arte-miy333 [17]

Answer:

a = the lowest critical speed of the shaft 882.81 rad/s

b = new diameter 0.05m or 50mm

c = critical speed 1765.62rad/s

Explanation:

see the attached file

8 0

2 years ago

Notice that in each conversion factor the numerator equals the denominator when units are taken into account. A common error in

navik [9.2K]

Answer:

he factor for the temporal part 1.296 107 s² = h²

m / s² = 12960 km / h²

Explanation:

This is a unit conversion exercise.

In the unit conversion, the size of the object is not changed, only the value with respect to which it is measured is changed, for this reason in the conversion the amount that is in parentheses must be worth one.

In this case, it is requested to convert a measure km/h²

Unfortunately, it is not clearly indicated what measure it is, but the most used unit in physics is m / s² , which is a measure of acceleration. Let's cut this down

the factor for the distance is 1000 m = 1 km

the factor for time is 3600 s = 1 h

let's make the conversion

m / s² (1km / 1000 m) (3600 s / 1h)²

note that as time is squared the conversion factor is also squared

m / s² = 12960 km / h²

the factor for the temporal part 1.29 107 s² = h²

6 0

2 years ago

A superhero swings a magic hammer over her head in a horizontal plane. The end of the hammer moves around a circular path of rad

Korolek [52]

Answer:

9.21954 m/s

54 m/s²

Angle is zero

Explanation:

r = Radius of arm = 1.5 m

$\omega$ = Angular velocity = 6 rad/s

The horizontal component of speed is given by

$v_h=\omega r\\\Rightarrow v_h=6\times 1.5\\\Rightarrow v_h=9\ m/s$

The vertical component of speed is given by

$v_v=2\ m/s$

The resultant of the two components will give us the velocity of hammer with respect to the ground

$v=\sqrt{v_h^2+v_v^2}\\\Rightarrow v=\sqrt{9^2+2^2}\\\Rightarrow v=9.21954\ m/s$

The velocity of hammer relative to the ground is 9.21954 m/s

Acceleration in the vertical component is zero

Net acceleration is given by

$a_n=a_h=\omega^2r\\\Rightarrow a_n=6^2\times 1.5\\\Rightarrow a_n=54\ m/s^2$

Net acceleration is 54 m/s²

As the acceleration is towards the center the angle is zero.

3 0

2 years ago