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2 years ago

10

The image shows positions of the earth and the moon in which region would an astronaut feel the lightest

2 answers:

DanielleElmas [232]2 years ago

8 0

Answer:

The moon region

Explanation:

trapecia [35]2 years ago

5 0

Answer:

The moon region

Explanation:

This is because there is little to no gravity on the moon. That is where the astronaut would feel the lightest.

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Charge q1 is distance r from a positive point charge q. charge q2=q1/3 is distance 2r from q. what is the ratio u1/u2 of their p

makvit [3.9K]

We need the power law for the change in potential energy (due to the Coulomb force) in bringing a charge q from infinity to distance r from charge Q. We are only interested in the ratio U₁/U₂, so I'm not going to bother with constants (like the permittivity of space).

<span>The potential energy of charge q is proportional to </span>
<span>∫[s=r to ∞] qQs⁻²ds = -qQs⁻¹|[s=r to ∞] = qQr⁻¹, </span>

<span>so if r₂ = 3r₁ and q₂ = q₁/4, then </span>
<span>U₁/U₂ = q₁Qr₂/(r₁q₂Q) = (q₁/q₂)(r₂/r₁) </span>
<span>= 4•3 = 12.</span>

5 0

2 years ago

In a certain region of space, a uniform electric field has a magnitude of 4.30 x 104 n/c and points in the positive x direction.

denis23 [38]

The magnetic force exerted by a field E to a charge q is given by F=Eq. In this case, F=4.30*10^4*(6.80mu C). 1mu C=10^-6C, so F=4.30*6.80=10^-2=0.29N. The direction is in the x direction, the direction that the field is applied because the charge is positive.

5 0

2 years ago

jenny's model train is set up on a circular track. There are six telephone poles evenly spaced around the track. It takes the en

d1i1m1o1n [39]

Answer:

T = 60 s

Explanation:

There are 6 poles on the track which are equally spaced

so the angular separation between the poles is given as

$\theta = \frac{2\pi}{6}$

$\theta = \frac{\pi}{3}$

so the angular speed of the train is given as

$\omega = \frac{\theta}{t}$

$\omega = \frac{\pi}{30} rad/s$

now we have time period of the train given as

$T = \frac{2\pi}{\omega}$

$T = \frac{2\pi}{\frac{\pi}{30}}$

$T = 60 s$

5 0

2 years ago

A magnetic dipole with a dipole moment of magnitude 0.0243 J/T is released from rest in a uniform magnetic field of magnitude 57

ololo11 [35]

Answer:

47.76°

Explanation:

Magnitude of dipole moment = 0.0243J/T

Magnetic Field = 57.5mT

kinetic energy = 0.458mJ

∇U = -∇K

Uf - Ui = -0.458mJ

Ui - Uf = 0.458mJ

(-μBcosθi) - (-μBcosθf) = 0.458mJ

rearranging the equation,

(μBcosθf) - (μBcosθi) = 0.458mJ

μB * (cosθf - cosθi) = 0.458mJ

θf is at 0° because the dipole moment is aligned with the magnetic field.

μB * (cos 0 - cos θi) = 0.458mJ

but cos 0 = 1

(0.0243 * 0.0575) (1 - cos θi) = 0.458*10⁻³

1 - cos θi = 0.458*10⁻³ / 1.397*10⁻³

1 - cos θi = 0.3278

collect like terms

cosθi = 0.6722

θ = cos⁻ 0.6722

θ = 47.76°

7 0

2 years ago

Read 2 more answers

Kiting during a storm. The legend that Benjamin Franklin flew a kite as a storm approached is only a legend — he was neither stu

Dvinal [7]

Answer:

The current is $I = 1.1434*10^{-5}}\ A$

Explanation:

From the question we are told that

The radius of the kite string is $R = 2.02 mm = 0.00202 \ m$

The distance it extended upward is $D = 0.823 km = 823 \ m$

The thickness of the water layer is $d = 0.506 mm = 0.000506 \ m$

The resistivity is $\rho = 159\ \Omega \cdot m$

The potential difference is $V = 186 MV = 186 *10^{6} \ V$

Generally the cross sectional area of the water layer is mathematically represented as

$A = \pi r^2$

Here r is mathematically represented as

$r = [(R + d ) - R]$

=> $r = [(0.00202 + 0.000506 ) - 0.00202]$

=> $r = 0.000506$

=> $A = 3.142 * [0.000506]^2$

=> $A = 8.0447*10^{-7}\ m^2$

Generally the resistance of the water is mathematically represented as

$R = \frac{\rho * D }{A}$

=> $R = \frac{159 *823 }{8.0447*10^{-7}}$

=> $R = 1.62662 * 10^{11} \ \Omega$

Generally the current is mathematically represented as

$I = \frac{V}{R}$

=> $I = \frac{186 *10^{6} }{1.62662 * 10^{11}}$

=> $I = 1.1434*10^{-5}}\ A$

8 0

2 years ago