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Georgia [21]
1 year ago
7

Two boys want to balance a seesaw perfectly. One boy weighs 120 pounds and is sitting four feet from the fulcrum. The other boy

weighs 80 pounds. Where should the lighter boy sit to balance the seesaw?
Physics
1 answer:
OLEGan [10]1 year ago
6 0

Basically a distance multiplied by a weight that is equal to the distance that is going to be multiplied by the weight. (for the equation we will use X for the distance).

equation: 4 x1 20 = ? x 80

Now step one: 4(120) = X(80)  

Or another way is 480 = 80X  

480/80 = X  

48/8= X  

X = 6

I hope this could help! Sorry if it didn't make much sense otherwise!


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Explanation:

Initial time, t₁ = 2:30 pm

Final time, t₂ = 2:30:45

We need to find the motion of students in terms of time. Final time is 45 seconds more than the initial time.

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\Delta t=t_2-t_1\\\\\Delta t=2:30:45-2.30\\\\\Delta t=45\ s

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1 year ago
Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45-m-diamete
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Explanation:

It is given that,

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Radius of the semicircle, r = 22.5 m      

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The greyhound is moving under the action of centripetal acceleration. Its formula is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(15)^2}{22.5}

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We know that, g=9.8\ m/s^2

a=\dfrac{10\times g}{9.8}

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Hence, this is the required solution.                                              

5 0
1 year ago
A child is riding a merry-go-round that has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745 ra
skelet666 [1.2K]

Answer:

So the acceleration of the child will be 8.05m/sec^2

Explanation:

We have given angular speed of the child \omega =1.25rad/sec

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Angular acceleration \alpha =0.745rad/sec^2

We know that linear velocity is given by v=\omega r=1.25\times 4.65=5.815m/sec

We know that radial acceleration is given by a=\frac{v^2}{r}=\frac{5.815^2}{4.65}=7.2718m/sec^2

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7 0
2 years ago
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andrey2020 [161]
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sin 60 = ax / 9.4
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Answer:

Explanation:

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