To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch
1 answer:
Answer:
man upward acceleration is 0.14m/s^2
Explanation:
given data:
mass of man = 72 kg
downward force = 360 N
The mass of man of weight 72 kg is hang from two sections of rope, one section pf rope ties around man waist and other section is ties in man hands. when he pulls down the rope with 360 N force then each section of rope pulls with 360 N
we know that
Weight= mass × gravity= 72kg × 9.8 = 705.6N
Force = mass× acceleration
Force= -705.6 + (2 × 358) = 10.4 N
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Explanation:
The given data is as follows.
Mass of small bucket (m) = 4 kg
Mass of big bucket (M) = 12 kg
Initial velocity () = 0 m/s
Final velocity () = ?
Height = 2 m
and, = 0 m
Now, according to the law of conservation of energy
starting conditions = final conditions
235.44 = + 78.48
= 4.43 m/s
Thus, we can conclude that the speed with which this bucket strikes the floor is 4.43 m/s.
Answer:
(2) −1 e
Explanation:
A quark is the lightest elementary particles which form hadron such as proton and neutron. A quark has fractional charge.
Up, charm and top quarks have charge where as down, strange and bottom quarks have
charge.
The antiparticle of up quark is antiup quark and has charge charge.
The antiparticle of down quark is antidown quark and has charge charge.
An antibaryon is composed of two anti-up quark and one anti-down quark.
Net charge of the anti-baryon is:
Thus, antibaryon has -1e charge.
Answer:
a)
b)
Explanation:
Given that
v(t) = 5 t i + t² j - 2 t³ k
We know that acceleration a is given as
Therefore the acceleration function a will be
The acceleration at t = 2 s
a= 5 i + 2 x 2 j - 6 x 2² k m/s²
a=5 i + 4 j -24 k m/s²
The magnitude of the acceleration will be
a= 24.83 m/s²
The direction of the acceleration a is given as
a)
b)