The label on the box of cleanser states that it contains ch3cooh. what elements are in this compound.

Any kind of wave spreads out after passing through a small enough gap in a barrier. This phenomenon is known as _________. a) di

bulgar [2K]

Answer:

a) diffraction

Explanation:

Diffraction occurs when waves pass through small openings, around obstacles or sharp edges.When an opaque object is between the point of light and a screen, the border between the shaded and illuminated regions on the screen is not defined. A careful inspection of the scrubber shows that a small amount of light is diverted to the shaded region. The region outside the shadow contains bright and dark altered bands, where the intensity of the first band is brighter than the region of uniform illumination.

6 0

2 years ago

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Diesel engines give more miles per gallon than gasoline engines, but some of this is due to the higher energy content of diesel

Lina20 [59]

Answer:

0.106

Explanation:

For 1 liter of diesel the car can get 19 km, if it takes 0.2 MJ for each km then it would take the total energy of 19*0.2 = 3.8 MJ to move an aerodynamic car 19 km. Since 1 liter of of diesel also contains 36 MJ in internal energy, then the efficiency of the diesel engine is the ratio of its output energy over its input energy:

$\frac{3.8}{36} = 0.106$

5 0

2 years ago

A brick of mass 2 kg is dropped from a rest position 5 m above the ground. what is its velocity at a height of 3 m above the gro

Rina8888 [55]

We can solve the problem by using the law of conservation of energy.

Using the ground as reference point, the mechanical energy of the brick when it is at 5 m from the ground is just potential energy (because the brick is initially at rest, so it doesn't have kinetic energy):
$E= U = mgh=(2 kg)((9.81 m/s^2)(5 m)=98.1 J$

when the brick is at h'=3 m from the ground, its mechanical energy is now sum of kinetic energy and potential energy:
$E= K+U= \frac{1}{2} mv^2 + mgh'$

where v is the velocity of the brick. Since E is conserved, it must be equal to the initial energy (98.1 J), so we can solve this equation to find v:
$v= \sqrt{ \frac{2(E-mgh')}{m} }=6.3 m/s$

8 0

2 years ago

: The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop

Sholpan [36]

Answer:

Fa=774 N

Fb=346 N

Explanation:

We will solve this problem by equating forces on each axis.

On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒ $Fa*sin(50)-Fb*sin(20)=0$