Density=mass/volume
5.45g/ml=65g/V
V=65g/5.42g/ml
V=11.92ml
Assumption both thunder and misty are pulling in same direction,
Net force= 1000N+800N-75N=1725N
Mass of wagon = 1725N/1.3ms^-2 = 1327kg
Answer:
a) V = 1.866 10² V
, b) V = 3.424 10⁵ V
, c) v = 8.1 10⁶ m / s
Explanation:
a) the potential difference is requested to accelerate the electrons up to 2.7% of the speed of light
v = 0.027 c
v = 0.027 3 10⁸
v = 8.1 10⁶ m / s
for this part we can use the conservation of mechanical energy
starting point. When electrons are at rest
Em₀ = U = q V
final point. Electrons with maximum speed
Em_f = K = ½ m v2
Em₀ = Em_{f}
e V = ½ m v²
V = ½ m v² / e
let's calculate
V = ½ 9.1 10⁻³¹ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 1.866 10² V
V = 1866 V
b) if this acceleration protons is the mass of the proton is m_{p} = 1.67 10-27
V = ½ 1.67 10⁻²⁷ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 3.424 10⁵ V
V = 342402 V
c)
this potential difference should give the protons the same speed as the electrons
v = 8.1 10⁶ m / s
<h2>
Answer: a.The mirrors and eyepiece of a large telescope are spring-loaded to allow them to return quickly to a known position. </h2>
Explanation:
Adaptive optics is a method used in several astronomical observatories to counteract in real time the effects of the Earth's atmosphere on the formation of astronomical images.
This is done through the insertion into the optical path of the telescope of sophisticated deformable mirrors supported by a set of computationally controlled actuators. Thus obtaining clear images despite the effects of atmospheric turbulence that cause the unwanted distortion.
It should be noted that with this technique it is also necessary to have a moderately bright reference star that is very close to the object to be observed and studied. However, it is not always possible to find such stars, so a powerful laser beam is used to point towards the Earth's upper atmosphere and create artificial stars.
<em>To determine the y component of velocity of a projectile </em><u><em>sine </em></u><em>operation is performed on the angle of launch.</em>
<u>Answer:</u> <em>sine</em>
<u>Explanation:</u>
Thus 
The initial velocity u can be resolved along two directions.
Along the X direction initial velocity = u cos θ
Along y direction initial velocity= u sin θ
From the equation of motion 
Thus velocity along x direction
=u cos θ
Velocity along y direction
= u sinθ -gt
Sign of g is negative.