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olasank [31]
2 years ago
10

Buffalo, New York, experienced a snowstorm November 13–21, 2014. Residents refer to the event as “Snowvember.” What was the like

ly cause of this snowfall?
Physics
2 answers:
prohojiy [21]2 years ago
7 0

Answer:

<h2>Lake-Effect Snow.</h2>

Explanation:

November 13–21, 2014 North American winter storm was a tragic event which is remembered until this days. Experts say that this "snowstorm" was originated from the Pacific Northwest, bringing a rich amount of lake-effect snow.

Lake-Effect snow occurs with cold air, when it pass across the open waters of the Great Lakes. Different variables as warmth and moisture are involved, when the air raises to atmosphere creates heavy snow falls.

scZoUnD [109]2 years ago
5 0
I know you're probably done with this by now, but the answer is *Lake-Effect Snow*
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A 1.0-m-long copper wire of diameter 0.10 cm carries a current of 50.0 A to the east. Suppose we apply to this wire a magnetic f
Setler79 [48]

Answer:

The classification of that same issue in question is characterized below.

Explanation:

The given values are:

Current, I = 50.0 A

Diameter, d = 0.10 cm

(a)...

As we know,

⇒  Magnetic force = Copper wire's weight

So,

⇒   B\times I\times L=M\times g

On putting the estimated values, we get

⇒  B\times 50\times 1=7.037\times 10^{-3}\times 9.81

⇒  50B=69.03297\times 10^{-3}

⇒  B=1.38\times 10^{-3} \ T

(b)...

As we know,

⇒  m=\delta\times L\times \frac{\pi \ d^2}{4}

⇒      =8960\times 1\times \frac{\pi \ (0.001)^2}{4}

⇒      =2240\times \pi \ 0.000001

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7 0
2 years ago
A CCD has a greatest possible pixel value of 4095. what is the bit level of this CCD?
Shtirlitz [24]
<span>Bit level for a CCD (Charged coupled device) with a greatest possible pixel value of 4095:The relationship between the bit level and pixel value is given as:pixel value = 2^bit level.Most charged coupled devices (CCDs) have 8-bit, 16-bit, 32-bit levels.Using simple mathematics, we can see that 2^12 = 4096.Since the maximum number of pixels is 4095, the bit level is 12., i.e. the CCD has 12-bit level.</span>
8 0
2 years ago
Calculate the force of gravity between two objects of masses 1300 kg and 7800 kg, which are 0.23 m apart.
uranmaximum [27]

Answer:

F = Gm1m2/r^2 where G = 6.67x10^-11, m1 =1300, m2 = 7800, r = 0.23m

F = 6.67x10^-11 *1300*7800/(0.23)^2 = 0.0127852N

Explanation:

6 0
2 years ago
A 36,287 kg truck has a momentum of 907,175 kg • m/s. What is the trucks velocity.
Airida [17]

Momentum = Mass x Velocity

Put the values where they belong and solve for Velocity.

In this case, since Mass is being multiplied by Velocity, to solve for be Velocity you would divide both sides by Velocity.  The velocity will equal the momentum divided by the mass.

4 0
2 years ago
An object at rest is suddenly broken apart into two fragments by an explosion one fragment acquires twice the kinetic energy of
satela [25.4K]
<span>First, we use the kinetic energy equation to create a formula: Ka = 2Kb 1/2(ma*Va^2) = 2(1/2(mb*Vb^2)) The 1/2 of the right gets cancelled by the 2 left of the bracket so: 1/2(ma*Va^2) = mb*Vb^2 (1) By the definiton of momentum we can say: ma*Va = mb*Vb And with some algebra: Vb = (ma*Va)/mb (2) Substituting (2) into (1), we have: 1/2(ma*Va^2) = mb*((ma*Va)/mb)^2 Then: 1/2(ma*Va^2) = mb*(ma^2*Va^2)/mb^2 We cancel the Va^2 in both sides and cancel the mb at the numerator, leving the denominator of the right side with exponent 1: 1/2(ma) = (ma^2)/mb Cancel the ma of the left, leaving the right one with exponent 1: 1/2 = ma/mb And finally we have that: mb/2 = ma mb = 2ma</span>
8 0
2 years ago
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