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rjkz [21]
2 years ago
9

A circuit is supplied with 60 VDC and contains two series resistors with values of 100 and 400 . What is the total current in th

e circuit?
A. 2 A
B. 0.82 A
C. 1.2 A
D. 0.12 A

What circuit quantity is measured by connecting a meter's test leads in series with an energized component?
A. Resistance
B. Power
C. Voltage
D. Current
Physics
1 answer:
scoundrel [369]2 years ago
6 0

When resistors are connected in series, they act like
a single resistor whose resistance is their sum. 

100 ohms and 400 ohms, connected in series, look like
a single resistor of 500 ohms.

           Current = (voltage) / (resistance)

                        = (60 volts) / (500 ohms) = 0.12 A.
________________________
<span>
Current is measured by connecting a meter in series
with an energized component.  In other words, a break
is made in the circuit, the meter is connected in the break,
and the current to be measured literally flows through the meter.</span>

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Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance
scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

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Second minima from center

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\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

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8 0
2 years ago
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As we know that

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7 0
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