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Yakvenalex [24]
3 years ago
7

A car with a mass of 1,324 kilograms, traveling at a speed of 20 meters/second, crashes into a wall and stops. What is the kinet

ic energy after this perfectly inelastic collision?
A. 0.0 joules
B. 3.2 × 103 joules
C. 1.0 × 104 joules
D. 1.3 × 104 joules ...?
Physics
2 answers:
Valentin [98]3 years ago
7 0
I think the correct answer from the choices listed above is option A. The kinetic energy after the perfectly inelastic collision would be zero Joules. <span>A </span>perfectly inelastic collision<span> occurs when the maximum amount of kinetic energy of a system is lost. Hope this answers the question.</span>
Ksenya-84 [330]3 years ago
5 0

Answer:

A. 0.0 joules

Explanation:

We can calculate the initial kinetic energy of the car, which is given by:

K=\frac{1}{2}mv^2 = \frac{1}{2}(1,324 kg)(20 m/s)^2=2.65\cdot 10^5 J

where m is the mass of the car and v its initial speed. After the collision, the car stops, so its final speed is zero. Therefore, the new kinetic energy of the car will be

K=\frac{1}{2}(1,324 kg)(0 m/s)^2 = 0 J

This type of collision is called 'perfectly inelastic collision', and it occurs when there is the maximum loss of kinetic energy, as in this case. Therefore, the correct answer is

A. 0.0 joules

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Explanation:

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A segment of wire of total length 2.0 m is formed into a circular loop having 5.0 turns. If the wire carries a 1.2-A current, de
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Magnetic field at the center of the loop B=5.89\times 10^{-5}\ T.

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8 0
2 years ago
A box is being pulled by two ropes. Eduardo pulls to the left with a force of 500 N, and Clara pulls to the right with a force o
sergejj [24]

Answer:

kinetic friction or something else

Explanation:

Draw a diagram to illustrate the problem, as shown below.

m = mass of the box, kg

mg =  weight of the box, N, acting downward

Because of Newton's 3rd law, a normal force of N = mg acts upward on the box.

C = 200 N, the force applied by Clara, horizontally to the right

E = 500 N, the force applied by Eduardo, horizontally to the left.

Because E is greater than C, the box will move left.

The frictional force, F, will resist the initial motion. Its magnitude is

F = μN = μmg, where μ = kinetic coefficient of friction.

F acts horizontally to the right.

From the given table, we can conclude that

Normal force acting upward is correct

Tension by Eduardoacting left is correct.

Tension by Clara acting right is correct.

Kinetic friction acting left is Incorrect.

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Answer:

The direction of the kinetic friction force is incorrect

8 0
2 years ago
Two vectors are presented as a=3.0i +5.0j and b=2.0i+4.0j find (a) a x b, ab (c) (a+b)b and (d) the component of a along the dir
Svet_ta [14]
Let's ask this question step by step:
 Part A) 
 a x b = (3.0i + 5.0j) x (2.0i + 4.0j) = (12-10) k = 2k
 ab = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
 Part (c)
 (a + b) b = [(3.0i + 5.0j) + (2.0i + 4.0j)]. (2.0i + 4.0j)
 (a + b) b = (5.0i + 9.0j). (2.0i + 4.0j)
 (a + b) b = 10 + 36
 (a + b) b = 46
 Part (d)
 comp (ba) = (a.b) / lbl
 a.b = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
 lbl = root ((2.0) ^ 2 + (4.0) ^ 2) = root (20)
 comp (ba) = 26 / root (20)
 answer
 2k
 26
 46
 26 / root (20)
3 0
2 years ago
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