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eduard
1 year ago
8

A simple pendulum 0.64m long has a period of 1.2seconds. Calculate the period of a similar pendulum 0.36m long in the same locat

ion.
Physics
1 answer:
weqwewe [10]1 year ago
8 0

The period of the second pendulum is 0.9 s

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity at the location of the pendulum

For the first pendulum, we have

L = 0.64 m

T = 1.2 s

Therefore we can find the value of g at that location:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{1.2})^2 (0.64)=17.5 m/s^2

Now we can find the period of the second pendulum at the same location, which is given by

T=2\pi \sqrt{\frac{L}{g}}

where we have

L = 0.36 m (length of the  second pendulum)

g=17.5 m/s^2

Substituting,

T=2\pi \sqrt{\frac{0.36}{17.5}}=0.9 s

#LearnwithBrainly

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From the image:

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h = 1.1548m

When Jeff reaches his lowest point his potential energy is converted to kinetic energy

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v = \sqrt{2gh}

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Tension in the string at the lowest point is sum of weight of Jeff and the his centripetal force

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An airplane travels horizontally at a constant velocity v. An object is dropped from the plane and one second later another obje
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Answer:

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