Answer:
(Downwards)
(Towards Left)
Explanation:
As we know that beam is in equilibrium
So here we can use torque balance as well as force balance for the beam
Now by torque balance equation at the pivot we can say
As we know that
mg = 1.40 kN
F = 5 kN
so we will have
Now force balance in vertical direction
(Downwards)
Force balance in horizontal direction
(Towards Left)
Answer:
Kinetic energy is given by:
K.E. = 0.5 m v²
Susan has mass, m = 25 kg
Velocity with which Susan moves is, v = 10 m/s
Hannah has mass, m' = 30 kg
Velocity with which Hannah moves is, v' = 8.5 m/s
<u>Kinetic energy of Susan:</u>
0.5 m v² = 0.5 × 25 kg × (10 m/s)² = 1250 J
<u>Kinetic energy of Hannah:</u>
0.5 m v'² = 0.5 × 30 kg × (8.5 m/s)² = 1083.75 J
Susan's kinetic energy is <u>1250 J </u>and Hannah's kinetic energy is <u>1083.75 J</u>.
Since kinetic energy is dependent on mass and square of speed. Thus, speed has a greater effect than mass. As it is evident from the above example. Susan has greater kinetic energy due to higher speed than Hannah.
Answer:
When reviewing the results, the correct one is C
Explanation:
The right hand rule is widely useful in knowing the direction of force in a maganto field,
The ruler sets the thumb in the direction of the positive particle, the fingers extended in the direction of the magnetic field, and the palm in the direction of the force.
Let's apply this to our exercise.
The thumb that is the speed goes in the negative direction of the axis,
The two extended that the magnetic field look negative x,
The span points entered the dear sheet the negative the Z axis
When reviewing the results, the correct one is C
Answer:
The force that the wire exerts on the electron is 
Explanation:
Given that,
Current = 8.60 A
Velocity of electron 
Position of electron = (0,0.200,0)
We need to calculate the magnetic field
Using formula of magnetic field
Put the value into the formula
We need to calculate the force that the wire exerts on the electron
Using formula of force
Hence, The force that the wire exerts on the electron is
