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bekas [8.4K]
2 years ago
10

Ryan is experimenting with core materials for an electromagnet. He slides different core materials through a coil of current-car

rying wire. Sort the core materials based on whether they will or won’t increase the strength of Ryan’s electromagnet.
Physics
2 answers:
Fudgin [204]2 years ago
7 0

Answer:

We can say that electromagnet is coils of wire which behave like bar magnets with a distinct South and North poles when a current of electricity passes through the coil.

The bigger the strength of Ryan's electromagnet, the better the conductivity of the material.

The material is as follows,

1. Silver and it is the best conductor.

2. Iron.

3. Nickel

4. Steel.

5. Glass which is an insulator, and

6. wood which is an insulator, and we thoroughly know that insulators they don't conduct electricity.

Explanation:

Arte-miy333 [17]2 years ago
5 0
Will increase strength: iron, nickel, steel
won't increase strength: wood, silver, glass

^thats on Plato
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allochka39001 [22]

Explanation:

It is given that,

Speed of a wave, v = 251 m/s

Wavelength of the wave, λ = 5.1 cm = 0.051 m

(1) The frequency of the wave is given by :

\nu=\dfrac{v}{\lambda}

\nu=\dfrac{251\ m/s}{0.051\ m}

\nu=4921.56\ Hz

(2) Angular frequency of the wave is given by :

\omega=2\pi\nu

\omega=2\pi\times 4921.56\ Hz

\omega=30923.07\ rad/s

(3) The period of oscillation is given by T as :

T=\dfrac{1}{\nu}

T=\dfrac{1}{4921.56}

T = 0.000203 seconds

or

T = 0.203 milliseconds

Hence, this is the required solution.

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2 years ago
The number of significant figures on the measurement 0.050010 kg id
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A car traveling at speed v takes distance d to stop after the brakes are applied. What is the stopping distance if the car is in
Vikki [24]

49d

<h3>Further explanation</h3>

This case is about uniformly accelerated motion.

<u>Given:</u>

The initial speed was v takes distance d to stop after the brakes are applied.

<u>Question:</u>

What is the stopping distance if the car is initially traveling at speed 7.0v?

Assume that the acceleration due to the braking is the same in both cases. Express your answer using two significant figures.

<u>The Process:</u>

The list of variables to be considered is as follows.

  • \boxed{u \ or \ v_i = initial \ velocity}
  • \boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}
  • \boxed{a = acceleration \ (constant)}
  • \boxed{d = distance \ travelled}

The formula we follow for this problem are as follows:

\boxed{ \ v^2 = u^2 + 2ad \ }

  • a = acceleration (in m/s²)
  • u = initial velocity  
  • v = final velocity
  • d = distance travelled

Step-1

We substitute v as the initial speed, distance of d, and zero for final speed into the formula.

\boxed{ \ 0 = v^2 + 2ad \ }

\boxed{ \ v^2 = -2ad \ }

Both sides are divided by -2d, we get \boxed{ \ a = \Big( -\frac{v^2}{2d} \Big) \ . . . \ (Equation-1) \ }

Step-2

We substitute 7.0v as the initial speed, zero for final speed, and Equation-1 into the formula.

\boxed{ \ 0 = (7.0v)^2 + 2 \Big( -\frac{v^2}{2d} \Big)d' \ }

Here d' is the stopping distance that we want to look for.

\boxed{ \ 2 \Big( \frac{v^2}{2d} \Big)d' = (7.0v)^2 \ }

We crossed out 2 in above and below.

\boxed{ \ \Big( \frac{v^2}{d} \Big)d' = 49.0v^2 \ }

We multiply both sides by d.

\boxed{ \ v^2 d' = 49.0v^2 d \ }

We crossed out v^2 on both sides.

\boxed{\boxed{ \ d' = 49.0d \ }}

Hence, by using two significant figures, the stopping distance if the car is initially traveling at speed 7.0v is 49d.

<h3>Learn more</h3>
  1. Determine the acceleration of the stuffed bear brainly.com/question/6268248
  2. Particle's speed and direction of motion brainly.com/question/2814900
  3. About the projectile motion brainly.com/question/2746519

Keywords: a car traveling at speed v, takes distance d to stop after the brakes are applied, the stopping distance, if the car is initially traveling at speed 7.0v, the acceleration due to the braking is the same, two significant figures.

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Answer:

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Explanation:

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K = F/AS^2=996/(83×20^2)

K= 996/33200 = 0.03

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Answer:

210.3 degrees

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Use the x and y coordinates of net force to get the direction

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