Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete
1 answer:
Answer:
<em>work done in pumping the entire fuel is 466587 J</em>
<em></em>
Explanation:
weight of the gasoline per volume = 6600 N/m^3
diameter of the tank = 3 m
length of the tank = 2 m
height of the tractor tank above the top of the tank = 5 m
work done in pumping fuel to this height = ?
First, we find the volume of the fuel
since the tank is cylindrical,<em> we assume that the fuel within also takes the cylindrical shape.</em>
<em>Also, we assume that the fuel completely fills the tank.</em>
volume of a cylinder =
where r = radius = diameter ÷ 2 = 3/2 = 1.5 m
volume of the cylinder = 3.142 x x 2 = 14.139 m^3
we then find the total weight of the fuel in Newton
total weight = (weight per volume) x volume
total weight = 6600 x 14.139 = 93317.4 N
work done = (total weight of the fuel) x (height through which the fuel is pumped)
work done in pumping = 93317.4 x 5 = <em>466587 J</em>
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Answer:
The heat transferred from water to skin is 6913.5 J.
Explanation:
Given that,
Weight of water = 25.0 g
Suppose that water and steam, initially at 100°C, are cooled down to skin temperature, 34°C, when they come in contact with your skin. Assume that the steam condenses extremely fast. We will further assume a constant specific heat capacity c=4190 J/(kg°K) for both liquid water and steam.
We need to calculate the heat transferred from water to skin
Using formula for stream
Put the value into the formula
Hence, The heat transferred from water to skin is 6913.5 J.