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Rudiy27
2 years ago
7

Step 8: Observe How Changes in the Speed of the Bottle Affect Beanbag Height

Physics
2 answers:
lina2011 [118]2 years ago
6 0

Answer:

When the speed of the bottle is 2 m/s, the average maximum height of the beanbag is <u>0.10</u>  m.

When the speed of the bottle is 3 m/s, the average maximum height of the beanbag is<u> 0.43</u>  m.

When the speed of the bottle is 4 m/s, the average maximum height of the beanbag is  <u>0.87</u> m.

When the speed of the bottle is 5 m/s, the average maximum height of the beanbag is  <u>1.25</u> m.

When the speed of the bottle is 6 m/s, the average maximum height of the beanbag is  <u>1.86</u> m.

Sorry for not answering early on! If anyone in the future needs help, I got these answers from 2020 egenuity, though I can't post the picture for proof. Stay Safe!

MaRussiya [10]2 years ago
4 0

Answer:

0.10

0.43

0.87

1.25

1.86

Explanation:

I just did this

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Answer: Option (b) is the correct answer.

Explanation:

As Kristina is over training, therefore, there is pain in her muscles because human body also requires rest in order to work or function properly.

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2 years ago
Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so
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As per kinematics equation we are given that

v^2 = v_o^2 + 2ax

now we are given that

a = 2.55 m/s^2

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from above equation we have

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0 = 475.24 + 5.1 x

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7 0
2 years ago
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What is the temperature when a solid begins to liquefy
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Answer:

Explanation:

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2 years ago
Suppose a rectangular piece of aluminum has a length D, and its square cross section has the dimensions W XW, where D (W x W) to
Ludmilka [50]

Answer:

R₂ / R₁ = D / L

Explanation:

The resistance of a metal is

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Where ρ is the resistivity of aluminum, L is the length of the resistance and A its cross section

We apply this formal to both configurations

Small face measurements (W W)

The length is

         L = W

Area  

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Large face measurements (D L)

       Length L = D= 2W

       Area     A = W L

     R₂ = ρ D / WL = ρ 2W / W L = 2 ρ/L

The relationship is

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2 years ago
Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m ea
madreJ [45]
In order to answer this exercise you need to use the formulas

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