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2 years ago

Step 8: Observe How Changes in the Speed of the Bottle Affect Beanbag Height

Physics

2 answers:

lina2011 [118]2 years ago

6 0

Answer:

When the speed of the bottle is 2 m/s, the average maximum height of the beanbag is 0.10 m.

When the speed of the bottle is 3 m/s, the average maximum height of the beanbag is 0.43 m.

When the speed of the bottle is 4 m/s, the average maximum height of the beanbag is 0.87 m.

When the speed of the bottle is 5 m/s, the average maximum height of the beanbag is 1.25 m.

When the speed of the bottle is 6 m/s, the average maximum height of the beanbag is 1.86 m.

Sorry for not answering early on! If anyone in the future needs help, I got these answers from 2020 egenuity, though I can't post the picture for proof. Stay Safe!

MaRussiya [10]2 years ago

4 0

Answer:

0.10

0.43

0.87

1.25

1.86

Explanation:

I just did this

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A (1.25+A) kg bowling ball is hung on a (2.50+B) m long rope. It is then pulled back until the rope makes an angle of (12.0+C)o

daser333 [38]

Answer:

F = 0.535 N

Explanation:

Let's use the concepts of energy, at the highest and lowest point of the trajectory

Higher

Em₀ = U = mg y

Lower

$Em_{f}$ = K = ½ m v²

Emo = $Em_{f}$

mg y = ½ m v2

v = √ 2gy

y = L - L cos θ

v = √ (2g L (1-cos θ))

Now let's use Newton's second law n at the lowest point where the acceleration is centripetal

F = ma

a = v² / r

In turning radius is the cable length r = L

F = m 2g (1-cos θ)

Let's calculate

F = 2 1.25 9.8 (1 - cos 12)

F = 0.535 N

7 0

2 years ago

If Pete ( mass=90.0kg) weights himself and finds that he weighs 30.0 pounds, how far away from the surface of the earth is he

shutvik [7]

Answer: 9938.8 km

Explanation:

1 pound-force = 4.48 N

30.0 pounds-force = 134.4 N

The force of gravitation between Earth and object on the surface of is given by:

$F = \frac{GMm}{R^2} = mg$

Where M is the mass of the Earth, m is the mass of the object, R (6371 km) is the radius of the Earth.

At height, h above the surface of the Earth, the weight of the object:

$(mg)'= \frac{GMm}{(R+h)^2}$

we need to find "h"

taking the ratio of two:

$\frac{mg}{(mg)'}=\frac{(R+h)^2}{R^2}\\ \Rightarrow \frac{90kg \times 9.8 m/s^2}{134.4 N}=\frac{(R+h)^2}{R^2}\\ \Rightarrow 6.56 R^2= (R+h)^2 \Rightarrow h= (2.56-1)R\\ \Rightarrow h = 1.56 R = 1.56 \times 6371 km = 9938. 8 km$

Hence, Pete would weigh 30 pounds at 9938.8 km above the surface of the Earth.

5 0

2 years ago

Rita has two small containers, one holding a liquid and one holding a gas. Rita transfers the substances to two larger container

Temka [501]

Answer: liquids take the shape of the container they are in, but have definite volume. like liquids the shape of a gas changes with the container. unlike liquids the volume of a gas changes depending on the container it is in

Explanation:

4 0

2 years ago

Read 2 more answers

one horsepower is a unit of power equal to 746w. how much energy can a 150-horsepower engine transform in 10.0s?

Dafna1 [17]

1 watt = 1 joule/second

1 horsepower = 746 watts = 746 joule/second

(150 horsepower) x (746 watt/HP) x (1 joule/sec / watt) x (10 sec)

= (150 x 746 x 1 x 10) joule = 1,119,000 joules .
if correct plz mark brainly

8 0

1 year ago

When Jim and Rob ride bicycles, Jim can only accelerate at three-quarters the acceleration of Rob. Both startfrom rest at the bo

Natali5045456 [20]

Answer:

46.4 s

Explanation:

5 minutes = 60 * 5 = 300 seconds

Let g = 9.8 m/s2. And $\theta$ be the slope of the road, s be the distance of the road, a be the acceleration generated by Rob, 3a/4 is the acceleration generated by Jim . Both of their motions are subjected to parallel component of the gravitational acceleration $gsin\theta$