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valentina_108 [34]
2 years ago
11

The circuit below represents four resistors connected to a 12-volt source. What is the total current in the circuit? 4.0Ω 6.0Ω 1

2 V, 8.0Ω 6.0Ω

Physics
2 answers:
Tpy6a [65]2 years ago
8 0

Answer:

For series connected resistors I = 0.5A

For parallel connected resistors I = 8.5A

Explanation:

Since the diagram is not available, our solution will be divided into two;

According to ohm's law which states that "the current passing through a,metallic conductor at constant temperature is directly proportional to the potential difference across its ends. Mathematically, E = IRt where;

E is the electromotive force

I is the total current in the circuit

Rt is total equivalent resistance.

Where E = 12volts

Rt can be gotten depending on the arrangements of the resistors which can either be in series or parallel.

If the resistors are in series, their equivalent resistance gives;

Rt = 4.0Ω+6Ω+8Ω+6Ω

Rt = 24Ω

The current I will be;

I = E/Rt = 12/24

I = 0.5A

If the connection is in series, the total current in the circuit will be 0.5A.

For resistance in parallel;

1/Rt = 1/4Ω+1/6Ω+1/8Ω+1/6Ω

1/Rt = 6+4+3+4/24

1/Rt = 17/24

Rt = 24/17Ω

I = E/Rt

I = 12/(24/17)

I = 12×17/24

I = 8.5A

If the connection is in parallel, the total current in the circuit will be 8.5A

jekas [21]2 years ago
6 0

Explanation:

Below are attachments to the question and answer to the incomplete question.

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Official (Closed) - Non Sensitive
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Answer:

The minimum running time is 319.47 s.

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First we find the distance covered and time taken by the train to reach its maximum speed:

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Time taken to reach maximum speed = t₁

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Now, we shall calculate the end time and distance covered by train, when it comes to rest on next station.

We have:

Final Speed = Vf = 0 m/s    (Since, train is finally stops)

Initial Speed = Vi = 29.17 m/s     (The train must maintain max. speed for min time)

Deceleration = a = - 0.7 m/s²

Distance Covered to stop = s₂

Time taken to stop = t₂

Using 1st equation of motion:

Vf = Vi + at₂

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t₂ = (0 m/s - 29.17 m/s)/(- 0.7 m/s²)

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s₃ = 7 km - s₂ - s₁

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t₃ = s₃/v

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