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Kryger [21]
2 years ago
5

At constant temperature, the volume of the container that a sample of nitrogen gas is in is doubled. As a result the pressure of

the nitrogen gas is halved. The amount of nitrogen gas is unchanged in this process. This is an example of:
A) Boyle's Law
B) Avogadro's Law
C) Charle's Law
D) Dalton's Law
E) Gay-Lussac's Law
Physics
1 answer:
In-s [12.5K]2 years ago
6 0

Answer:

A) Boyle's Law

Explanation:

Boyle's Law states that pressure is inversely proportional to volume if the temperature and volume remain constant in closed system

{P}=\frac{1}{V}

{P_1}\times {V_1}={P_2}\times {V_2}

As it is seen here the volume and temperature remain constant but the volume of the container is doubled.

So, this is an example of Boyle's Law.

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Explanation:

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A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen
Svetllana [295]

Answer:

h_p = 30.46\ m

Explanation:

<u>Free Fall Motion</u>

A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.

The speed vf of the object when a time t has passed is given by:

v_f=g\cdot t

Where g = 9.8 m/s^2

Similarly, the distance y the object has traveled is calculated as follows:

\displaystyle y=\frac{g\cdot t^2}{2}

If we know the height h from which the object was dropped, we can solve the above equation for t:

\displaystyle t=\sqrt{\frac{2\cdot y}{g}}

The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:

\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec

The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:

t_2=2.56 - 2 = 0.56\ sec

Therefore, it has traveled down a distance:

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Thus, the height of the pen is:

h_p = 32 - 1.54\Rightarrow h_p=30.46\ m

8 0
2 years ago
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