Let h = the distance from the edge of the wall to the water surface (m).
Use g = 9.8 m/s² and neglect air resistance.
The initial vertical velocity of the pebble is zero.
Because the pebble hits the surface of the water after 1.5 s, therefore
h = (1/2)*(9.8 m/s²)*(1.5 s)² = 11.025 m
Answer: 11.025 m
Answer:
The value is 
Explanation:
From the question we are told that
The Coulomb constant is 
The charge on the electron/proton is 
The mass of proton 
The mass of electron is 
Generally for the electron to be held up by the force gravity
Then
Electric force on the electron = The gravitational Force
i.e




Answer:
0.5 m
Explanation:
Givens:
ym1 = 2.5 mm
ym2 = 4.5 mm
Ф_1=π / 4
Ф_2=π / 2
We have 2 ways to solve this problem. The first one given that the 2 waves have the frequency then we know that the resultant wave amplitude is
Ym = (ym1 + ym2)cos(Ф_2/2)
By substitution we have
Ym= (0.025 + 0.045)cos(π/4) = 0.496 m
The second one is it treat them as Phasors where the phase between them is Ф_2=π / 2 Therefore
Ym^2=(ym1^2+ym2^2)
So we have Ym=√0.025^2+0.045^2
= 0.5 m
For this case we have that by definition:

Where,
- <em>m: mass of the object
</em>
- <em>a: acceleration of the object
</em>
- <em>F: summation of forces
</em>
We have then:

Then, by clearing the acceleration we have:

Substituting values we have:

Answer:
The acceleration of the box is equal to:

Answer:

Explanation:
Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies
where r is the distance
Since intensity is given then when at 3 m


Since we have the constant then at 4m
Intensity, 