Given that the lenth write steel l =3.80m fastened celling mass m= 54.0kg
v = s/t
v = 3.8/0.0492
v = 77.23 m/s
now, the formula for speed in a wire is
v = ( T/ÎĽ )^1/2
where T is the tension in the string and ÎĽ is the mass pee unit length.
v = ( Tl/m )^1/2 .......(replace ÎĽ with m/l)
now T = 550N
v = [ 550(3.8)/m ]^1/2
squaring both sides
v^2 = 550(3.8)/m
v^2 = 2090/m
putting the value of v calculated above and solving
m =0.35 kg
Answer:
114.86%
Explanation:
In both cases, there is a vertical force equal to the sprinter's weight:
Fy = mg
When running in a circle, there is an additional centripetal force:
Fx = mv²/r
The net force is found with Pythagorean theorem:
F² = Fx² + Fy²
F² = (mv²/r)² + (mg)²
F² = m² ((v²/r)² + g²)
F = m √((v²/r)² + g²)
Compared to just the vertical force:
F / Fy
m √((v²/r)² + g²) / mg
√((v²/r)² + g²) / g
Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:
√((12²/26)² + 9.8²) / 9.8
1.1486
The force is about 114.86% greater (round as needed).
To calculate the acceleration of the wooden block, we use the expression F=ma where F is the force applied, m is the mass of the object and a is the acceleration. We calculate as follows:
F = ma
4.9 = 0.5a
a = 9.8
Hope this answers the question. Have a nice day.
If the boat's velocity is 18m/sec relative to the water in the river and not the shore, it would need to be added the river speed of 2.5m/sec to get a total of 20.5m/sec. The 20.5m/sec would then be the total velocity of the boat relative to the shore. From personal experience, I know that when one runs with the tide, one is adding the tide flow speed to one's boat speed (what it would be in neutral waters) to get a sometimes much faster speed.