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1 year ago

If a 5.0 kg box is pulled simultaneously by a 10.0 N force and a 5.0 N force, then its acceleration must be?

Physics

1 answer:

kicyunya [14]1 year ago

6 0

For this case we have that by definition:

$F = ma$

Where,

m: mass of the object
a: acceleration of the object
F: summation of forces

We have then:

$F = 10 + 5\\F = 15 N$

Then, by clearing the acceleration we have:

$a = \frac {F} {m}$

Substituting values we have:

$a = \frac {15} {5}\\a = 3 \frac {m} {s ^ 2}$

Answer:

The acceleration of the box is equal to:

$a = 3 \frac {m} {s ^ 2}$

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A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done b

stepan [7]

The work done by a system kept at constant pressure is given by:
$W=p \Delta V = p (V_f - V_i)$
where
p is the pressure
$V_f$ is the final volume
$V_i$ is the initial volume

If we plug the numbers given by the problem into this equation, we find
$W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm$

And since $1 atm \cdot L = 101.3 J$ , we have that the work done is
$W= 1.00 atm \cdot L = 101.3 J$

8 0

1 year ago

Read 2 more answers

A tennis ball bounces on the floor three times, and each time it loses 23.0% of its energy due to heating. how high does it boun

Anika [276]

1.8 meters Since the ball loses 23.0% of it's energy with each bounce, that means that it retains 100% - 23.0% = 77.0% of it's energy per bounce. And since it bounces 3 times, that means that it will have 0.77^3 = 0.456533 = 45.6533% of it's original energy after the third bounce. So it will reach 45.6533% of it's original height after the third bounce. So 45.6533% * 4.0 = 0.456533 * 4.0 m = 1.8 m

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2 years ago

If a rock is thrown upward on the planet mars with a velocity of 14 m/s, its height (in meters) after t seconds is given by h =

crimeas [40]

Answer:

Velocity of rock after 2 seconds = 6.56 m/s

Explanation:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Here height of rock in meters, h = $14t-1.86t^2$

Comparing both the equations

We will get initial velocity = 14 m/s(already given) and $\frac{1}{2} a = -1.86$

So, Acceleration, a = -3.72 $m/s^2$

Now we have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

When time is 2 seconds we need to find final velocity.

v = 14 - 3.72 * 2 = 6.56 m/s.

So, Velocity of rock after 2 seconds = 6.56 m/s

6 0

2 years ago

Whose research showed that atoms consist of small positively charged nuclear centers and lots of empty space populated by electr

Tju [1.3M]

Answer:

Rutherford

Explanation:

Basic principles of the Rutherford atomic model.

1. Positively charged particles are in a very small volume compared to the size of the atom.

2. Most of the mass of the atom is in that small central volume. Rutherford did not call it "core" in his initial papal but he did it from 1912.

3. Electrons with negative electrical charge revolve around the nucleus.

4. The electrons rotate at high speeds around the nucleus and in circular paths that it called orbits.

5. Both negatively charged electrons and the positively charged nucleus are held together by an electrostatic attraction force.

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1 year ago

What is the threshold frequency for sodium metal if a photon with frequency 6.66 × 1014 s−1 ejects a photon with 7.74 × 10−20 J

FrozenT [24]

Answer:

5.5 × 10^14 Hz or s^-1

no orange light has less frequency so no photoelectric effect

Explanation:

hf = hf0 + K.E

HERE h is Planck 's constant having value 6.63 × 10 ^-34 J s

f is frequency of incident photon and f0 is threshold frequency

hf0 = hf- k.E

6.63 × 10 ^-34 × f0 = 6.63 × 10 ^-34× 6.66 × 10^14 - 7.74× 10^-20

6.63 × 10 ^-34 × f0 = 3.64158×10^-19

f0 = 3.64158×10^-19/ 6.63 × 10 ^-34

f0 = 5.4925 × 10^14

f0 =5.5 × 10^14 Hz or s^-1

frequency of orange light is 4.82 × 10^14 Hz which is less than threshold frequency hence photo electric effect will not be observed for orange light

8 0

1 year ago