The axoplasm of an axon has a resistance Rax. The axon's membrane has both a resistance (Rmem) and a capacitance (Cmem). A singl
e segment of an axon can be modeled by a circuit with Rmem and Cmem in parallel with each other and in series with an open switch, a battery, and Rax?.
Imagine the voltage of the battery is ?V?.
Imagine that after a very long time there is a current I going through the battery. The potential difference across the membrane can be written as I Rmem.
Write down another expression for the potential difference across the membrane using all or some of the given variables, except Rmem.
Imagine the voltage of the battery is ?V?.
Imagine that after a very long time there is a current I going through the battery. The potential difference across the membrane can be written as I Rmem.
Write down another expression for the potential difference across the membrane using all or some of the given variables, except Rmem.
1 answer:
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Answer:
The rotational frequency must be 2073.56 rpm
Explanation:
Notice that we need to obtain a rotational frequency in "rpm" (revolutions per minute), so we better start by converting all the given information into the appropriate units:
The magnitude of the velocity for the pitch is given in miles per hour, while the diameter of the machine's wheels is given in cm. Let's reduce all units of length into meters(using the metric system), and the units of time into minutes.
Conversion of the 85 mph speed into meters per minute:
Recall that 1 mile equals 1609.34 meters, and that 1 hour equals 60 minutes, so we write:
which can be rounded to approximately 2280 m/min.
We also convert the 35 cm diameter into meters:
diameter = 0.35 m
Now we use the equation that relates angular velocity (w) and the radius (R) of the circular movement, with tangential velocity (), in order to obtain the angular velocity of the wheel:
but recall that this angular velocity is given in radians per unit of time. So first find the radius of the wheel (half its diameter). R = 0.175 m
So we have:
And now, recalling that radians equal one revolution, we convert the angular velocity ot revolutions per minute by dividing the "w" we found by
:
rotational frequency =
Complete Question
The complete Question is shown on the first uploaded image
Answer:
a
The torque acting on the particle is
b
The magnitude of the angular momentum increases relative to the origin
Explanation:
From the equation we are told that
The position of the particle is
The mass of the particle is
The time is t
The torque acting on the particle is mathematically represented as
where is change in angular momentum which is mathematically represented as
Where X mean cross- product
is the velocity which is mathematically represented as
Substituting for
Now the cross product of is mathematically evaluated as
So the angular momentum becomes
Substituting for m
Substituting into equation for torque
The magnitude of the angular momentum can be evaluated mathematically as
From the is equation we see that the magnitude of the angular momentum is varies directly with square of the time so it would relative to the origin because at the origin t= 0s and we move out from origin t increases hence angular momentum increases also
Answer:
Isothermal : P2 = ( P1V1 / V2 ) , work-done
Adiabatic : : P2 = , work-done =
W =
Explanation:
initial temperature : T
Pressure : P
initial volume : V1
Final volume : V2
A) If expansion was isothermal calculate final pressure and work-done
we use the gas laws
= PIVI = P2V2
Hence : P2 = ( P1V1 / V2 )
work-done :
B) If the expansion was Adiabatic show the Final pressure and work-done
final pressure
where y = 5/3
hence : P2 =
Work-done
W =
Where